What is the correct pronunciation of the following words A. Dirty (Chu ò) regret (CH à ng) biting (Ji á o) character B, gully (H è) Dai (D à I) Zong let bygones be bygones (Ji ū) C, letter (Qi ā n) gift (C ì) no message (Y ǎ o) d, gloomy (ā n) analysis (P ō U) MA libing

What is the correct pronunciation of the following words A. Dirty (Chu ò) regret (CH à ng) biting (Ji á o) character B, gully (H è) Dai (D à I) Zong let bygones be bygones (Ji ū) C, letter (Qi ā n) gift (C ì) no message (Y ǎ o) d, gloomy (ā n) analysis (P ō U) MA libing

The right one is a

The more idioms or four character words with Li pronunciation, the better,

Reciprocity
try fair means before resorting to force
Cater to inside and outside
The force is infinite
turn back the powers of darkness
one 's strength does not match one 's ambitions
do one 's utmost to hold one 's own opinion against that of the majority
be visible before the eyes
appear to be tough outwardly , be timid inwardly
taken for granted
grief at separation and joy in union
the wrong person
alienate one person from another
no kernels or seeds are gathered , as in a year of scarcity
Patter, patter, patter
appear united outwardly but divided at heart
Separation of bone and flesh

What are the idioms or four character words at the end of "red"
As long as the pronunciation is "red", one, two, three, four tones are OK

Colorful
rosy lips and pretty white teeth
Exceptionally jealous
The willows are green and the flowers are red in the evening
Dark green, light red, colorful

In △ ABC, a = 80, B = 100, a = 30 °, then the number of solutions of B is ()
A. 0b. 1C. 2D. Not sure

Because a = 80, B = 100, a = 30 °, according to the sine theorem: Asina = bsinb, substitute SINB = 58, because B ∈ (0, π), so B = arcsin58 or B = π - arcsin58, so choose C

The two passenger and freight cars leave from a and B at the same time. Three hours later, the two cars meet. At this time, the bus runs 60% of the whole journey. It is known that the bus runs 72 times more than the truck
Kilometer, the distance between a and B

72÷[60%-(1-60%)]
=72÷0.2
=360 km

High school mathematics geometry (urgent yo)
It is known that circle C is a circle with radius 1 and center (3,4). Point P moves on the circle. Find the maximum and minimum values of the square of (AP) + (BP) and the corresponding coordinates of P

A(-1,0) B(1,0)?
Is that so
Method 1: use a conclusion: the sum of squares of parallelogram diagonal is equal to the sum of squares of four sides (coordinate method, vector method, cosine theorem can be proved)
Cut off half of the parallelogram, leaving the triangle and the middle line. From the above conclusion, we can get that | AP | ^ 2 + | BP | ^ 2 = (4po ^ 2 + AB ^ 2) / 2, where o is the coordinate origin. Therefore, to minimize the sum of squares, we only need to minimize Po (AB = 2 is known)
Obviously, when OPC is collinear, Po is the smallest, where C is the center of the circle and O is the origin
The minimum value of Po is | OC | - 2 = 3
So the minimum value of | AP | ^ 2 + | BP | ^ 2 = (36 + 4) / 2 = 20
Method 2: let P point coordinate be (x, y), then | AP | ^ 2 + | BP | ^ 2 = (x + 1) ^ 2 + y ^ 2 + (x-1) ^ 2 + y ^ 2 = 2 (x ^ 2 + y ^ 2) + 2 = 2PO ^ 2 + 2
To minimize the above formula, we only need to minimize Po. Obviously, when OPC is collinear, Po is the minimum, where C is the center of the circle
The minimum value of Po is | OC | - 2 = 3
So the minimum value of | AP | ^ 2 + | BP | ^ 2 = 20

There are 840 tons of goods in the freight yard, which are transported by Party A and Party B. Party A has 12 vehicles with a load of 5 tons, and Party B has 15 vehicles with a load of 3 tons

5*12=60
3*15=45
840/(60+45)=8
That is to say, each team runs 8 times per car

Simplification of "a square · (B-C) + b square · (C-A) + C square · (a-b) = 0"

A square · (B-C) + b square · (C-A) + C square · (a-b) = 0
a²b-a²c+b²a-b²a+c²（a-b）=0
a-b)(c²-ac-bc+ab）=0
(a-b)(c-a)(c-b）=0
It's just simplification,

The speed of train is 60% faster than that of car. How much slower is the speed of car than that of train?

6 = 37.5% a: the speed of a car is 37.5% slower than that of a train

As shown in the figure, triangle ABC and triangle CDE are equilateral triangles, and a, C, e are collinear
Prove the included angle of straight line AC and BD

After appraisal, this topic not only has no picture, but also has no truth
The question is almost always the angle between AD and be. The figure is almost always that B and D are on the same side of the line AE, and C is on the line AE. The answer is almost always 60 degrees
Let ad be in o,
Equilateral triangle shows that ∠ DCE = ∠ ACB = 60 ° and by collinear, we can get ∠ ACD = ∠ BCE = 120 ° and AC = BC, CD = CE, SAS get △ ACD ≌ △ BCE, ∠ DAC = ∠ EBC, in △ BCE, ∠ EBC + ∠ BCE + ∠ CEB = 180 ° so ∠ DAE + ∠ CEB = ∠ EBC + ∠ CEB = 60 ° in △ AOE, ∠ AOB = ∠ DAE + ∠ CEB = 60 ° is an acute angle, so it is the angle between AD and be, the answer is 60 °
I don't understand. Even I, baidu Hi,