How to write the composition of unit 2 in the second volume of the fifth grade Chinese book?

How to write the composition of unit 2 in the second volume of the fifth grade Chinese book?

On a sunny afternoon, a group of boys happily walked to the open space and piled their bags and hats into two piles. The fierce match began. The golden haired goalkeeper's face turned red with tension and joy. Although his knee was scratched yesterday, he didn't care. He put his hands on his knees and squatted, The little boy standing behind him, dressed in a red sportswear and with a big stomach, was a little unconvinced. Yesterday, when his elder brother broke his leg, he kicked away a ball and won. He thought of this, and was a little complacent. All the people in the past were attracted by the intense ball game. They stopped and sat on the bench. They didn't know whose dog it was, It's not interested in football, it's only interested in the little ball that the owner provides for it to play. Now it's doing nothing but snoring on the grass. You see, the little boy with his younger brother, his eyes tightly fixed on the yellow team, sitting here motionless for fear that the yellow team will lose. The little boy with golden hair, like the goalkeeper, craned his neck, He murmured to himself in a low voice: "come on! Kick! OK!" behind him, a little girl with a crimson butterfly Festival on her head,

For the fifth grade volume two unit composition picture small football match, to 500 words

On a sunny afternoon, a group of boys happily walked to the open space and piled their bags and hats into two piles. The fierce match began. The golden haired goalkeeper's face turned red with tension and joy. Although his knee was scratched yesterday, he didn't care. He put his hands on his knees and squatted, The little boy standing behind him, dressed in a red sportswear and with a big stomach, was a little unconvinced. Yesterday, when his elder brother broke his leg, he kicked away a ball and won. He thought of this, and was a little complacent. All the people in the past were attracted by the intense ball game. They stopped and sat on the bench. They didn't know whose dog it was, It's not interested in football, it's only interested in the little ball that the owner provides for it to play. Now it's doing nothing but snoring on the grass. You see, the little boy with his younger brother, his eyes tightly fixed on the yellow team, sitting here motionless for fear that the yellow team will lose. The little boy with golden hair, like the goalkeeper, craned his neck, "Come on! Kick! Good!" the little girl standing behind him, with a crimson butterfly Festival tied on her head, stood up and saw her hands akimbo, her brows wrinkled, as if something was wrong. The little girl in the red hat bent over, stretched her head and looked to the right, her face turned red, Although she didn't go to the "battlefield", her heart beat clearly. A girl with a doll in her arms kept smiling, but her eyes were busy. She kept staring at the ball to see where the ball was in the team. Maybe it was the first time that the little boy in Green saw such a scene. His little hand was counting the outcome, and he said, "it's wonderful, it's incredible." The most serious one is the big uncle. He is interested in it

Look at the picture, small football match composition 500 words

Point P is on the vertical bisector of line AB, if PA = 8, then Pb=______ ．

∵ point P is on the vertical bisector of line AB, ∵ PA = Pb, ∵ PA = 8, ∵ Pb = 8, so the answer is: 8

Simple calculation of 1 × 1 / 2 × 1 / 2 × 1 / 2 × 1 / 2 × 1 / 2

This is one fifth of the power of 2. Please clarify your question. If it's not easy to type, please indicate it in Chinese

If the generatrix length of the cone is 5cm and the high line length is 4cm, the bottom area of the cone is () cm2
A. 3πB. 9πC. 16πD. 25π

The bottom radius of the cone is r = 25 − 16 = 9 = 3, and the bottom area of the cone is π R2 = 9 π cm2

1-1 by 1 / 2 plus 1 / 2 by 1 / 3 until 1 / 50 by 1 / 51

1-1×1/2-1/2×1/3-…… -1/50×1/51
=1-(1-1/2)-(1/2-1/3)-…… -(1/50-1/51)
=1-1+1/2-1/2+1/3-…… -1/50+1/51
=1/51

Circle C passes through three different points P (k, 0), q (2, 0) and R (0, 1). It is known that the tangent slope of circle C at point P is 1. Try to find the equation of circle C

Let the equation of circle C be x2 + Y2 + DX + ey + F = 0, then K and 2 are two of x2 + DX + F = 0, ∧ K + 2 = - D, 2K = f, that is, d = - (K + 2), f = 2K, and then circle R (0, 1), so 1 + e + F = 0. ∧ e = - 2k-1. So the equation of circle C is x2 + Y2 - (K + 2) x - (2k + 1) y + 2K = 0, and the coordinates of circle center are (K + 22, 2K + 12) ∧ the tangent slope of circle C at point P is 1, ∧ KCP = - 1 = 2K + 12 − K, ∧ k = - 3. ∧ d = 1, e = 5, F =-6. The equation of circle C is x2 + Y2 + X + 5y-6 = 0

If the integer m makes 18m / (6m ^ 2 + 3M) a positive integer, what is the value of M?
Good score!

If you divide the upper and lower parts by m, you get 18 / (6m + 3). This is an integer, so 6m + 3 can only be equal to 3, or 2, or 9, or 6, or 1, or 18
M = 1

If the real numbers x and y satisfy 3.x2 + 2Y2 = 6x, the value ranges of X and X2 + Y2 are obtained respectively

The left side of the equation is nonnegative, so x > = 0
From 3x ^ 2 + 2Y ^ 2 = 6x, y ^ 2 = (6x-3x ^ 2) / 2 is obtained
x^2+y^2=-x^2/2+3x=-(x-3)^2/2+9/2 (x>=0)
So 0