Given a > 2, b > 2, try to judge whether the equation x * x - (a + b) x + AB = 0 and X * x-abx + (a + b) = 0 have common roots, please explain the reason * denotes a multiply sign The symbols can't be typed with words

Given a > 2, b > 2, try to judge whether the equation x * x - (a + b) x + AB = 0 and X * x-abx + (a + b) = 0 have common roots, please explain the reason * denotes a multiply sign The symbols can't be typed with words

No, let's assume that the two equations share a common value of x0, and substitute x0 into the two equations to get the following result:
(ab-a-b) x0 = (a + b-ab), the solution is x0 = - 1
When x0 = - 1, we substitute it into the original equation
1 + A + B + AB = 0, that is, (a + 1) (B + 1) = 0,
From a > 2, b > 2, we can know that a + 1 > 0, B + 1 >, then (a + 1) (B + 1) can not be 0, that is, the original equation has no common root

Given a ＞ 2, B ＞ 2, try to judge whether the equation X2 - (a + b) x + AB = 0 and X2 ABX + (a + b) = 0 have common roots. Please explain the reason

Let x 2 - (a + b) x + AB = 0 and X 2-abx + (a + b) = 0 have common roots. If x 0 is set, then x 20 − (a + b) x 0 + AB = 0. ① x 20 − ABX 0 + (a + b) = 0. Then (x 0 + 1) (a + b-ab) = 0

What's 37 times nine tenths? What's five and five tenths minus 3.25? What's 5.3 plus one and three tenths?

Question 1 = 33.3, question 2 = 13 / 4, question 3 = 6.6,

What is the tradition of classical Chinese

What's the tradition? The language is concise and concise

In square ABCD, M is a point on the edge of BC which is different from B and C, e is a point on the extension line of BC, and the bisector of am ⊥ Mn and intersecting DCE is n

Then △ ABC and △ FBM are isoisoisotriatriatriatriatriatriatriatriatriatriatriangles, BF = BM; also \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\80a △ MCN (AAS) ），∴AM=MN．

1 / 8 * 2.75 + 1 / 8 * 6.25-0.125 = simple calculation

1 / 8 * 2.75 + 1 / 8 * 6.25-0.125 = simple calculation
= 1/8 x ( 2.75 + 6.25 -1)
= 1/8 x 8
= 1

Three quadratic radical operations
1. The root sign 2x / y times the square of the root sign 2Y / 3x (Note: the square of X is not the square of 3x) times the square of the root sign x / 12Y (Note: the square of Y is not the square of 12Y)
2. Y / 4x / 9y / X
3. Radical X-Y △ square of X (x > 0)

1）3x
2) 3Y of 2x
3) X-Y of X
Ask me if you have any questions

In quadrilateral ABCD, ad is parallel to BC, and ad = 8cm, BC = 6cm. Point PQ starts from point a and C at the same time. Point P moves from point a to point d at the speed of 1cm / s, and point Q moves from point C to point B at the speed of 2cm / s. when one point of point P and Q reaches the end point, the other point stops
(1) How long after a quadrilateral abqp is a parallelogram?
(2) How long after a quadrilateral PQCD is a parallelogram?
8 mathematical parallelogram 3] [preferably according to parallelogram basis or judgment method]

(1) Let ABCP be a parallelogram after x seconds
According to a group of parallelograms whose opposite sides are parallel and equal, it is concluded that
1X＝6－2X X＝2s
(2) Similarly, as long as PD = CQ,
That is 8-x = 2x
x=16/3

Given (M & # 178; + n & # 178;) (M & # 178; + 1 + n & # 178;) = 6, find the value of M & # 178; + n & # 178;);

Let M & # 178; + n & # 178; = x,
x(x+1)=6
x=2,x=-3
∵m²+n²>0
∴m²+n²=2

65 + 63 + 61 + 59 +. + 7 + 5 + 3 + 1
Is the item number 33 counted or calculated, (65 + 1) / 2? How can we calculate the item number 65 + 63 + 61 + 59 +. + 9 + 7 + 5?

65 + 63 + 61 + 59 +. + 7 + 5 + 3 + 1 this is the arithmetic sequence, sum: (first + last) * number of terms / 2 number of terms: (last - first) * tolerance + 1 = (65 + 1) * 33 / 2 = 1089. You can change it to: 1 + 3 + 5 + 7 +. + 59 + 61 + 63 + 65 and use the formula again. As for how to get the number of terms: (first - last