If the rational number | a | = a, then the corresponding point of a on the number axis must be () A. Left side of origin B. The origin of the fire C. Right side of origin D. Origin or right side of origin

If the rational number | a | = a, then the corresponding point of a on the number axis must be () A. Left side of origin B. The origin of the fire C. Right side of origin D. Origin or right side of origin

If | a | is equal to - A, the corresponding point of rational number a on the number axis must be on the left side of the origin

If | a | = - A, then the corresponding point of rational number on the number axis must be ()

Origin and left of origin

If cos 31 ° is known to be m, then sin 239 ° Tan 149 ° is given=______ (expressed by an equation with m)

∵ cos31 ° = m, ∵ sin31 ° = 1 − cos231 ° = 1 − m2, sin239 ° = sin (270 ° - 31 °) = - cos31 °, tan149 ° = Tan (180 ° - 31 °) = - tan31 °, then sin239 ° tan149 ° = (- cos31 °); (- tan31 °) = cos31 ° tan31 ° = sin31 ° = 1 − m2

All the formulas about acceleration a

Just a moment

Given that K is a positive integer, try to find a value of K, so that the solution of the equation 5x minus 6K equals 1 / 2 (x minus 5K minus 1) about X is also a positive integer, and find the solution

5x-6k = 1 / 2 (x-5k-1) both sides simultaneously × 2
10x-12k = x-5k-1 the unknown x is on one side and the others on the other
9x = 7k-1. Because K is a positive integer, our result (the solution of x) is also a positive integer, so we first find a minimum K value so that 7k-1 is a multiple of 9 when k = 4,7k-1 = 27, x = 3
There are others that do the same thing
Hope to help you

If x = - 2 is the solution of the equation a (x + 3) = 12a + X, find the value of a2-a2 + 1

When a = - 4, a2-a2 + 1 = (- 4) 2 + 2 + 1 = 16 + 3 = 19

(2x & # 178;) & # 178; - 65x & # 178; Y & # 178; + (Y & # 178;) & # 178; factorization (cross multiplication)

Original formula = 4x ^ 4 + 4x & # 178; Y & # 178; + y ^ 4-69x & # 178; Y & # 178;
=(2x²+y²)²-69x²y²
=(2x²+y²+√69xy)(2x²+y²-√69xy)

If the point P is a (2a + B, - A + 1) about the X axis and B (4-b, B + 2) about the Y axis, what is the coordinate of point P

The point of P (x, y) about X axis symmetry is: P '(x, - y)
The point P with respect to the y-axis symmetry is p "(- x, y)
A system of equations can be set up as follows:
The equation is as follows
x=2a+b
-y=-a+1
-x=4-b
y=b+2
The solution: a = - 2, B = - 5
Then the coordinates of point P are: P (- 9, - 3)

If the domain of definition of function f (x) is R and both f (x) and f (x + 1) are odd functions, then the period of F (x) is zero

1

It is proved that the function f (x) = - 2x + 1 is a decreasing function on R

(1) It is proved that if any real number x1, X2, ∈ (- ∞, + ∞), and X1 < X2, then f (x1) - f (x2) = - 2x1 + 1 - (- 2x2 + 1) = - 2 (x1-x2), ∵ X1 < X2, ∵ x1-x2 < 0, - 2 (x1-x2) > 0, ∵ f (x1) - f (x2) > 0, that is, f (x1) > F (x2), ∵ function f (x) = - 2x + 1 is a decreasing function on R