The sinking and floating of objects Bottom sinking: F floating + FN = FN in G object When the density of the object is small, is it floating or sinking?

It's the supporting force. If it sinks to the bottom and contacts with the bottom, it may be affected by the supporting force of the bottom

Physics on the sinking and floating of objects, please process more detailed! Thank you
1. If an object with a mass of 600 grams and a volume of 500 cubic centimeters is thrown into the water, how will it move? What is the ultimate buoyancy? (two methods)
2. A hollow aluminum ball has a mass of 540 grams and a volume of 600 cubic centimeters. When it is thrown into the water, what is the buoyancy?
3. V a = v b = 100 cubic centimeter, the mass of a is 90 g, the mass of B is 100 g. after putting both a and B into water, what are their buoyancy? (two methods)

1: It can be seen from the question that the density of the object is greater than that of water, so do the sinking motion f = P water GV row = 52: F = g = 5.4 (floating state) 3: F1 = g = 0.9 (floating) F2 = g = 1 (floating)

Given that two acute triangles have two sides and an angle equal, can we prove the congruence of the two triangles? Can we prove the obtuse angle triangles
Another is that two acute angle triangles, two sides are proportional to one angle, can we prove that they are similar? Can we prove that obtuse angle

Two acute triangles are congruent when two sides and one angle are equal, but the obtuse angle is not necessarily
Triangle ABC & nbsp; and triangle ADC satisfy that two sides and one angle are equal, but they are not congruent, but they can not all be acute angle triangles, and they can all be obtuse angle triangles

As shown in the figure, in △ ABC, de ‖ BC, and s △ ade: s quadrilateral bced = 1:2, BC = 26. Find the length of de

∵ s △ ade: s quadrilateral bced = 1:2, s △ ABC = s △ ade + s quadrilateral DBCE, ∵ s △ ade: s △ ABC = 1:3, and ∵ de ‖ BC, ∵ ade ∵ ABC, ∵ s △ ade: s △ ABC = (DEBC) 2, and ∵ BC = 26, ∵ de = 22

What is the relationship between first derivative and second derivative of function and function image

The first derivative indicates the monotonicity of the image of the original function: in a certain interval, the first derivative > 0 indicates monotonic increasing, and the image is upward, and vice versa. In common, it is the slope
The second derivative indicates the convexity of the image of the original function, and the second derivative > 0 indicates that the image is convex,

It is known that a, B and C are all on the ellipse M: x ^ 2 / A ^ 2 + y ^ 2 = 1 (a > 0). The line AB, AC respectively passes through the left and right focus F1, F2 of the ellipse. When vector AC · vector F1F2 = 0, there are 9 vectors AF1 · vector af2 = vector AF1 ^ 2
① Let p be the diameter of any circle n: x ^ 2 + (Y-2) ^ 2 = 1 at any point EF on the ellipse m, and find the maximum value of vector PE · vector PF

① When vector AC · vector F1F2 = 0, af2 is perpendicular to F1F2,
9 vector AF1 · vector af2
=9|AF1||AF2|cosA=9|AF2|^2=|AF1|^2
=>|AF1 | = 3 | af2 |, AF1 | + | af2 | = 2A
=>|AF1|=3a/2,|AF2|=a/2,2c=|F1F2|=(√2)a
=>a^2=2(a^2-2)=>a^2=4
The equation of ellipse m is x ^ 2 / 4 + y ^ 2 / 2 = 1
② Let the coordinates of P, e and f be (2cos α, (√ 2) sin α), (COS β, 2 + sin β), (- cos β, 2-sin β)
Then vector PE · vector PF
=(cosβ-2cosα)(-cosβ-2cosα)+
(2+sinβ-(√2)sinα)(2-sinβ-(√2)sinα)
=4(cosα)^2-4(√2)sinα+2(sinα)^2+3
=-2(sinα)^2-4(√2)sinα+7
=11-2(sinα+√2)^2
When sin α = - 1, the maximum value of vector PE and vector PF is 5 + 4 √ 2

As shown in the figure, BP is the outer bisector of △ ABC, and point P is on the angle bisector of ∠ BAC. Verification: CP is the outer bisector of △ ABC

It is proved that: PD, PE, PF, BP are the outer angular bisector of △ ABC, PD ⊥ ad, PF ⊥ BC,  PD = PF (the distance from the point on the angular bisector to both sides of the angle is equal), ⊥ P is on the angular bisector of ∠ BAC, PD ⊥ ad, PE ⊥ AE, ⊥ PD = PE (the distance from the point on the angular bisector to both sides of the angle is equal), ⊥ pf = PE, PF ⊥ BC, PE ⊥ AE, ⊥ CP are △ a The bisector of the outer corner of BC (in the interior of the corner, the point with equal distance to both sides of the corner is on the bisector of the corner)

If x ＜ - 1, simplify | X-1 | + | x-4 | - | 5-2x|

If a (x, 5-x, 2x-1), B (4, 2, 3), when | ab | is the minimum, the value of X is equal to______ ．

AB = (4-x, x-3, 4-2x), so | ab | = (4-x) 2 + (x-3) 2 + (4-2x) 2 = 6x2-30x + 41 = 6 (x2-5x) + 41 = 6 (X-52) 2 + 72, so when x = 52, | ab | takes the minimum

Additional questions: as shown in the figure, it is known that △ ABC is inscribed in ⊙ o, AB is the diameter, ∠ CAE = ∠ B. verification: AE and ⊙ o are tangent to point a

It is proved that ∵ AB is the diameter, ∵ ACB = 90 degree, ∵ BAC + ∵ B = 90 degree, and ∵ CAE = ∵ B, ∵ BAC + ∵ CAE = 90 degree, that is, ∵ BAE = 90 degree, so AE and ⊙ o are tangent to point a

The sinking and floating of objects Bottom sinking: F floating + FN = FN in G object When the density of the object is small, is it floating or sinking?