Write the opening direction, axis of symmetry and vertex coordinates of the following parabola. When x is the value, what is the minimum or maximum value of Y? 《1》 The square of y = 3x + 2x "2" y = - x minus 2x 《3》 Y = - 2x square + 8x minus 8 "4" y = half x square minus 4x + 3 I'm not a student

Write the opening direction, axis of symmetry and vertex coordinates of the following parabola. When x is the value, what is the minimum or maximum value of Y? 《1》 The square of y = 3x + 2x "2" y = - x minus 2x 《3》 Y = - 2x square + 8x minus 8 "4" y = half x square minus 4x + 3 I'm not a student

1. Up, negative one-third, (negative one-third, negative one-third), when x = negative one-third, y is the smallest negative one-third
If there are square, downward, - 1, (- 1,1) after 2-x, and x = - 1, y is 1
When x = 2, y is 0
When x = 4, y is the smallest - 5

How to do question 30 on page 155 of ninth grade mathematics volume II (Beijing Normal University Edition)

As shown in the picture, there is a circus tent, its bottom is round, its radius is 20m, there is a straight fence from a to B, its length is 30m, the audience can watch the circus in the shadow area, if every square meter can stand three audience, then how many audience are watching the circus? (assuming the shadow area is full of audience) just find out the shape of this bow

The fourth power of 5 (A & sup3;) - 13 (the sixth power of a) & sup2;
The fourth power of 7x × the fifth power of X × (- the seventh power of x) + the fourth power of 5 (the fourth power of x) - (the eighth power of x) & sup2;

-8 (the 12th power of a)
-3 (the 16th power of x)

If x = ay = B is the solution of the equation 2x + y = 0, then 6A + 3B + 2=______ ．

Substituting x = ay = B into the equation 2x + y = 0, we get 2A + B = 0, ∩ 6A + 3B + 2 = 3 (2a + b) + 2 = 2

The ratio of 5.4 to 1 and 3 / 5 is () to the simplest integer ratio is ()

The ratio of 5.4:1 and 3 / 5 is (3:3 / 8) to the simplest integer ratio is (27:8)

From the 100 natural numbers from 1 to 100, arbitrarily take 51 numbers, of which there must be two numbers, and the difference between them is 50
From the 100 natural numbers from 1 to 100, arbitrarily take 51 numbers, of which there must be two numbers, and the difference between them is 50?
Plant 51 trees beside a 50 meter long path, please prove: no matter what, there are at least two trees whose distance is less than 1 meter?
In any seven different natural numbers, there must be two numbers whose difference is a multiple of 6. Why?
I know it's the drawer principle, the reason why I want each question! I can't write to help!

Do you use assumptions? Extreme thinking
Let's take 100 and 1 first, and make sure that the difference is the smallest, that is, 1,2,3,4. When you take 51 numbers, it is 50100-50 = 50,
Therefore, from the 100 natural numbers from 1 to 100, arbitrarily take 51 numbers, of which there must be two numbers, and the difference between them is 50

How to prove that the cubic of y = x is an increasing function on R?

Definition method:
Let any real number x1

How many decimeters are equal to square meters in 150 square meters

150 square kilometers = 74999999.99 square decimeters = 75000000 square meters

The absolute value of a divided by a + the absolute value of B divided by B + the absolute value of C divided by C + (a multiplied by B multiplied by C) divided by (a multiplied by B multiplied by C), the maximum value is m, and the minimum value is n, then (M + n) ^ 2004=
Everybody! Help me!

When a, B and C are all greater than 0, the maximum m is 1 + 1 + 1 + 1 = 4
When a, B and C are all less than 0, the minimum value n is - 1 + (- 1) + (- 1) + (- 1) = - 4
So (M + n) ^ 2004 = 0 ^ 2004 = 0

What is the derivative of √ (x-1)

y=(x-1)^(1/2)
So there is a power function derivative rule
y'=1/2*(x-1)^(-1/2)=1/[2√(x-1)]