I want to ask how to find the least common multiple when the first-order equation with one variable in grade seven goes to the denominator step by step Such as the title

Find the least common multiple of two numbers:
(1) If a is a multiple of B, then the least common multiple is a; if B is a multiple of a, then the least common multiple is B;
(2) If a is not a multiple of B, or B is not a multiple of a, and a and B have no greatest common divisor, then the least common multiple is the product of ab;
(3) If a is not a multiple of B, or B is not a multiple of a, and a and B have the greatest common divisor, then the least common multiple is a divided by the greatest common divisor multiplied by B or B divided by the greatest common divisor multiplied by A
Bonus points!

With the solution of unary linear equation to bracket and denominator, bracket means it is together!
Solution equation: 1. (5-7x) / 8 = (7-x) / 7
2.（（1-y）/3）-y=3-（（y+2）/2）
3.（（x+4）/0.2）-（（x-3）/0.5）=-1.3
4.（（5-0.1x）/1.2）-（（x-0.1）/2.4）=1

1.（5-7x）/8=（7-x）/7
7(5-7x)=8(7-x)
35-49x=56-8x
49x-8x=35-56
41x=-21
x=-21/41
2.（（1-y）/3）-y=3-（（y+2）/2）
2(1-y)-6y=18-3(y+2)
2-2y-6y=18-3y-6
6y+2y-3y=2+6-18
5y=-10
y=-2
3.（（x+4）/0.2）-（（x-3）/0.5）=-1.3
5(x+4)-2(x-3)=-1.3
5x+20-2x+6=-1.3
3x=-1.3-26
3x=-27.3
x=-9.1
4.（（5-0.1x）/1.2）-（（x-0.1）/2.4）=1
2(5-0.1x)-(x-0.1)=2.4
10-0.2x-x+0.1=2.4
1.2x=10.1-2.4
1.2x=7.7
x=77/12

Add 6 to a number, multiply by 6, subtract 6, and divide by 6. The result is 6. Find the number

〔(x+6)×6〕-6
————————=6
six
〔(x+6)×6〕-6=36
(x+6)×6=42
X + 6 = 7, the solution is x = 1

Let f (x) = Log1 / 2 (2-ax / x-1) (a is a constant and a

It is obvious that f (x) is a constant function when a = 2
There are many boundary problems in the derivation problem, and the test is very important

Simple calculation 101 * 26.9-1.25 * 26.9 * 0.8
9.99.9+0.99
3.70.2+4.5
67.2-7.8*4.9

101*26.9-1.25*26.9*0.8=101*26.9-1.25*0.8*26.9=101*26.9-26.9=（101-1）*26.9=26.9*100=26909.9*9.9+0.99=9.9*9.9+9.9*0.1=9.9*（9.9+0.1）=9.9*10=993.7*0.2+4.5=0.37*2+2.75*2=（0.37+2.75）*2=3.12*2=6.2467.2-...

(1) If | a | = 52, X and y are opposite numbers, m and N are reciprocal, find the value of the algebraic formula x + MNA + y. (2) given that a, B are opposite numbers, C and D are reciprocal, find the value of the algebraic Formula-2 (a + b) 2-cd2010 + 12010

(1) ∵ a | = 52, X and y are opposite numbers, m and N are reciprocal, a = ± 52, x + y = 0, Mn = 1, ∵ x + MNA + y = x + y + MNA = 0 + 1 ± 52 = ± 25; (2) ∵ A and B are opposite numbers, C and D are reciprocal, a + B = 0, CD = 1, ∵ - 2 (a + b) 2-cd2010 + 12010 = - 2 × 0-12010 + 12010 = 0

Why circle is the explanation of 360 degree super subversion

Let's take a look at 60,
sixty
= 1 X 60,
= 2 X 30,
= 3 X 20,
= 4 X 15,
= 5 X 12,
= 6 X 10,
This shows that,
It is quite convenient to divide 60 into two, three, four, five, six and ten parts,
As a result, the time and angle that often need to be equally divided are based on 60, as follows:
1 hour = 60 minutes,
1 minute = 60 seconds,
1 hour = 3600 seconds,
However, the eighth and ninth parts of 60 are not divisible,
After all, 3600 is too big,
So a circumference is set at 360 degrees,
three hundred and sixty
= 1 X 360,
= 2 X 180,
= 3 X 120,
= 4 X 90,
= 5 X 72,
= 6 X 60,
= 8 X 45,
= 9 X 40,
= 10 X 36,
= 12 X 30,
= 15 X 24,
Obviously, 360 is a lot more than 60,
360 degrees is more equal than 60 points,
Draw a circle with a compass and rotate it for one circle,
It's also 360 degrees,

The first row of determinant is 1110, the second row is 1101, the third row is 1011, and the fourth row is 0111

111011011011011c1 + C2 + C3 + C4 -- all columns are added to the first column 31103101311ri-r4, I = 1,2,3 -- all rows are subtracted from the fourth row, 000 - 100 - 100-1003111 = 3 (- 1) ^ 3 * (- 1) ^ (3 + 2 + 1) = - 3

(7.7 1.54) how to divide by 7

Because I don't know what symbol is in your middle
Train of thought
Remove the brackets and change to 7.7 △ 7 () 1.54 △ 7 = 1.1 () 0.2
Just fill in the symbol you left out

I want to ask how to find the least common multiple when the first-order equation with one variable in grade seven goes to the denominator step by step Such as the title