To pass the equation, to be able to understand the fourth grade 64*25*125 16*25*125

To pass the equation, to be able to understand the fourth grade 64*25*125 16*25*125

64*25*125
=(8*25)*(8*125)
=200*1000
=200000
16*25*125
=(4*25)*(4*125)
= 100*500
=50000

How to do the six questions on the fifth page of Mathematics
The height of a style on the square is 4 meters, the bottom radius is 0.5 meters, and the side and bottom of the style are covered with plastic flowers. If there are 40 flowers per square meter, how many burnt flowers are there on the style

First, calculate the surface area of the cylinder
Area of two bottom of cylinder: 0.45 π (PIE)
Side area: 4
Total area: 4.45 square meters
534

Chinese synchronous answers of Beijing Normal University Edition
Quality target detection 2

1. Read Pinyin and write words. (tears) (tenacity) (analysis) (felt boots) (vigorous) (graceful) (exquisite) (dry) (flag) (purge) 2. Compare words. Secret (secret) only (unique) Qiu (vigorous) upright (honey peach) but (afraid of falling behind) wine (wine) birthday (birth) 3

1、 2x+3.6*2=12.4 2、 3（x+3.6）=18.6 3、 x+3.5x=13.5

1、 2x+3.6*2=12.4 x=2.6
2 x=2.6
3 x=3

Use TaNx to denote Tan (x / 2)

tanx=2tan(x/2)/[1-tan^2(x/2)],tanx-tanx*tan^2(x/2)
=2tan(x/2),
tanx*tan^2(x/2)+2tan(x/2)-tanx=0
Do it yourself

Solving x ^ 4-x-20 ^ 2 by cross phase multiplication
X ^ 4 is the fourth power of X, and 20 ^ 2 is the square of 20

Irreducible (simplest)
You have the wrong number
Is it x ^ 4-x ^ 2-20
If it is, (x ^ 2-5) (x ^ 2 + 4)

It is known that m (x, y) is in the fourth quadrant, and the sum of its distances from the two coordinate axes is 12. The distance from m (x, y) to the X axis is greater than that to the Y axis
Then x = (y)=（

The distance to the x-axis | y | and the distance to the y-axis | X|
|x|+|y|=12,|y|-|x|=3
|y|=7.5,|x|=4.5
In the fourth quadrant
x=4.5,y=-7.5,

It is known that the maximum value of quadratic function f (x) = (LGA) x 2 + 2x + 4 LGA is 3, and the value of a is obtained

According to the maximum value of quadratic function, we can know that LGA < 0, and the maximum value of quadratic function is 4ac − b24a = 4 (LGA) 2 − 1lga = 3, that is, 4 (LGA) 2-3lga-1 = 0. The solution is: LGA = 1 (rounding off), LGA = - 14, that is, a = 10 − 14

Is a uniformly continuous function necessarily continuous

If the function f (x) is uniformly continuous on I, it is also continuous on I
Let f (x) be uniformly continuous on I, then for any point t on I, that is, t ∈ I;
F (x) is uniformly continuous. For any E > 0, there exists d > 0, if any two points a and B on I satisfy | a-b|

1. The first-order function y = KX + B (k is not equal to 0) intersects the X axis at the point () and the Y axis at the point ()
2. When the images of two functions are together, which image is above, which image corresponds to the function value (), and the function value of image () is equal
3, because any one variable linear equation can be transformed into ax + B = 0, (a, B are constants, a is not equal to 0), so the solution of one variable linear equation can be transformed into: when the value of a certain function is 0, find the value of the corresponding independent variable. From the image, this is equivalent to the known straight line y = KX + B. determine the value of () at the intersection of it and X axis

1. The intersection of linear function y = KX + B (k is not equal to 0) with X axis and point (- B / K, 0) with y axis and point (0, b)
2. Large intersection
3. Abscissa