It is known that the images of the linear functions Y1 = 2x + A and y2 = - x + B pass through the points a [- 2,0], and intersect with the Y axis at two points B.C It is known that the images of the first-order functions Y1 = 2x + A and y2 = - x + B pass through the points a [- 2,0], and intersect with the Y axis at two points B.C. (1) find the values of a and B; (2) draw the images of the two first-order functions in the same plane rectangular coordinate system; (3) find the area of △ ABC

It is known that the images of the linear functions Y1 = 2x + A and y2 = - x + B pass through the points a [- 2,0], and intersect with the Y axis at two points B.C It is known that the images of the first-order functions Y1 = 2x + A and y2 = - x + B pass through the points a [- 2,0], and intersect with the Y axis at two points B.C. (1) find the values of a and B; (2) draw the images of the two first-order functions in the same plane rectangular coordinate system; (3) find the area of △ ABC

First, find a. B, which are all linear functions, passing through point a (- 2,0). Then, take the abscissa and ordinate of point a into Y1 = 2x + A and y2 = - x + B respectively, that is, 0 = 2x (- 2) + A, 0 = - (- 2) + B can calculate a = 4, B = - 2

(2014 Shaanxi) 16. (3 points) it is known that P1 (x1, Y1), P2 (X2, Y2) are two points on the same inverse scale function image, if x2 = X1 + 2, and
=
+
Then the expression of the inverse function is

(2014 Shaanxi) 16. (3 points) it is known that P1 (x1, Y1), P2 (X2, Y2) are two points on the same inverse scale function image. If x2 = X1 + 2 and 1 / y2 = 1 / Y1 + 1 / 2, then the expression of the inverse scale function is as follows:
Let y = K / X
Y2 = K / x2: 1 / y2 = x2 / k.1
Y1 = K / X1: 1 / Y1 = X1 / K.2
X2 = X1 + 2: x2-x1 = 2.3
1/y2=1/y1+1/2
Substituting Formula 1 and 2 into:
x2/k=x1/k+1/2
(x2-x1)/k=1/2
By substituting formula 3, we get the following result:
2/k=1/2
k=4
So the expression is y = 4 / X