The equation of the circle symmetric with the circle X & sup2; + Y & sup2; - 2x-6y + 9 = 0 about the line x-y-1 = 0

The equation of the circle symmetric with the circle X & sup2; + Y & sup2; - 2x-6y + 9 = 0 about the line x-y-1 = 0

x²+y²-2x-6y+9=0
(x-1)²+(y-3)²=1
Center coordinates (1,3)
On the line x-y-1 = 0 symmetry point coordinates: (4,0)
The circular equation is
(x-4)²+y²=1

If circle X & sup2; + Y & sup2; - 4x + 6y = 0 and circle X & sup2; + Y & sup2; - 6x = 0 intersect at two points a and B, then the equation of the vertical bisector of AB is?

First, the two equations are used to calculate the coordinates of a and B, and then the midpoint coordinates are obtained by using the midpoint coordinate formula: half X1 + X2, half Y1 + Y2. Also, the slope of this straight line is multiplied by - 1 because it is a vertical bisector, and then it is set as a point oblique, and the midpoint coordinates can be brought in