If the sector area is 37.68 square centimeters and the radius of the circle is 6 centimeters, how long is the sector arc? How many degrees is the center angle?

Center angle = 37.68 / (3.14 * 6 ^ 2) * 360 = 120 degrees
Sector arc length = 3,14 * 2 * 6 * 120 / 360 = 12.56 cm

The radius of the circle where the sector is located is 3, its arc length is 14.13, and its central angle = ()

14.13 divided by 3 = 4.71

The diameter of the circle where the sector is located is 3, the central angle of the circle is 135 ° and its area = ()

Its area = 2.65

In a circle with an area of 12 square centimeters, what is the sector area of a 60 degree central angle

12 * (60 / 360) = 2 cm2
In a circle with an area of 12 square centimeters, the sector area of a 60 degree central angle is 2 square centimeters

When the central angle of a sector is 45 degrees, its area accounts for ()

The circle angle is 360 degrees, and 45 accounts for 1 / 8 of 360, so the area also accounts for 1 / 8 of the garden area in proportion

It is known that the area of a circle is 54 square centimeters and the sector area is 45 square centimeters. What is the central angle of the circle

360°x 45/54
=360°x 5/6
=300°

If the central angle of a circle is 45 ° and its area is 6.28 square centimeter, then the area of the circle where the circle is located is -------- square centimeter

"Mathematical answer group" for you to answer, I hope to help you
6.28 △ 45 × 360 = 50.24 square centimeter
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It is known that circle C1: (x-4) ^ 2 + y ^ 2 = 1, circle C2: x ^ 2 + (Y-2) ^ 2 = 1, circle C1 and C2 are symmetric with respect to line L
Given that circle C1: (x-4) ^ 2 + y ^ 2 = 1, circle C2: x ^ 2 + (Y-2) ^ 2 = 1, circle C1 and C2 are symmetric with respect to line L, the equation of line L is obtained

From the two circular equations, we can get their center points as follows:
C1：﹙4,0﹚,C2：﹙0,2﹚,
The midpoint of them is C (2,1),
From the coordinates of C1 and C2, the linear equations are obtained as follows
y=－½x＋2,
From the symmetry, we can assume that the linear equation of L is:
y=2x＋b,
Substituting the coordinates of point C into b = - 3,
The linear l equation is y = 2x-3

Given that circle C1: (x + 1) 2 + (Y − 1) 2 = 1, circle C2 and circle C1 are symmetric with respect to the straight line X-Y = 0, then the equation of circle C2 is ()
A. （x-1）2+（y+1）2=1B. （x-1）2+（y-1）2=1C. （x+1）2+（y+1）2=1D. （x+1）2+（y-1）2=1

∵ circle C1: (x + 1) 2 + (Y − 1) 2 = 1, the center C1 (- 1,1) of circle C1, radius R1 & nbsp; = 1, ∵ circle C2 and circle C1 are symmetric about the straight line X-Y = 0, ∵ circle C2's center C2 (1, - 1), radius R2 = 1, the equation of circle C2 is (x-1) 2 + (y + 1) 2 = 1

If the circle passes through two points AB and the center of the circle is on a straight line, the equation of the circle can be solved
How to solve the problem

For example, a straight line is known
y=kx+b
Let the center of the circle be (a, Ka + b), where K and B are known
Method 1: use the distance from the center of the circle to the point on the circle equal to the radius equation to solve the unknowns
Determine the center of the circle, and then use the distance from the center of the circle to the point on the circle to be equal to the radius, then the equation of the circle is solved
Method 2: 1
2. Let the equation of circle be (x-a) & sup2; + (y-ka-b) & sup2; = R & sup2;
Substituting the coordinates of a and B, a and R are solved
Find out the equation
I think method 1 is better and often used

If the sector area is 37.68 square centimeters and the radius of the circle is 6 centimeters, how long is the sector arc? How many degrees is the center angle?