(20 + 2x) (40-x) = 1200,

(20 + 2x) (40-x) = 1200,




(40-x) (20 + 2x) = 1200,


The original equation is sorted out
x²-30x+200=0
x²-30x=-200
x²-30x+225=-200+225
(x-15)²=25
Squared on both sides
x-15=±5
x=15±5
∴x1=20,x2=10



(40-x)(20+2x)=1200


(40-x)(20+2x)=1200
(40-x)(10+x)=600
400+30x-x²=600
x²-30x+200=0
(x-10)(x-20)=0
x₁=10、x₂=20



(20+2x)(40-x)=1200


(40-x)(20+2x)=1200
800+80X-20X-2x^2=1200
-2x^2+60X-400=0
x^2-30X+200=0
(X-10)(X-20)=0
X-10=0 X-20=0
X1=10 X2=20