(1) 1:5 3x + 3:2 1 = 8 (2) 4.3x-2.8x = 15 (3) 6x-2.5 = 9.5

(1) 1:5 3x + 3:2 1 = 8 (2) 4.3x-2.8x = 15 (3) 6x-2.5 = 9.5

(1) 1:5 3x + 3:2 1 = 8
8x/5=8-7/2
16x=45
x=45/16
(2) 4.3x-2.8x=15
1.5x=15
x=10
(3)
6x-2.5=9.5
6x=9.5+2.5
6x=12
x=2

Calculation: the second power of X - (3x + 5) (3x-5) + (2x + 1) (2x-1)

Original form
=X ^ 2 - (9x ^ 2-25) + (4x ^ 2-1) square difference formula
=x^2-9x^2+25+4x^2-1
=-4x^2+24
=-4(x^2-6)

How to calculate 1-3 / 2x = 3x + 5 / 2

Two sides of the equation are multiplied by 2x at the same time to get the quadratic equation 2x & sup2; + X + 1 = 0, which has no real solution@

Solving inequality 0.2 ^ 3x-5 less than 25 ^ x

0.2^(3x-5)

10x () = 3x out of 5 () = 3x out of 17 () = 0.25
10x () = 5 / 3x () = 1 / 7 3x () = 0.25x () = 1 is not liberation equation

One in ten, five in three, four in three

Thanks for your help. 2x-1 / 3-0.5 (3x-5) - x + 1 / 6 + 1.25 > 0

It should be (2x-1) / 3-0.5 (3x-5) - (x + 1) / 6 + 1.25 > 0
（4x-2)/6-(9x-15)/6-(x+1)/6+5/4>0
So x

How to solve 3 * 0.7 + 3x = 3.9

3*0.7+3x=3.9
3x=3.9-3*0.7
3x=3.9-2.1
3x=1.8
x=1.8÷3
x=0.6

The solution of 9 ^ X-6 * 3x-7 = 0
It's 3 ^ X

9^x-6*3^x-7=0
Let y = 3 ^ x, the original equation becomes:
y²-6y-7=0
(y-7)(y+1)=0
y1=7,3^x=7,x=log3(7)
Y2 = - 1,3 ^ x = - 1 (not rounding off)
9 ^ X-6 * 3x-7 = 0
x=log3(7)

How to write (9 * 0.7) * 3x = 1

(9*0.7)*3x=1
(9*0.7*3)*x=1
x=1/(9*0.7*3)
x=10/(9*7*3)
x=10/189

2 (0.3x + 4) - 5 (0.2x-1.8) = 1 to find the solution of X

2（0.3x+4）-5（0.2x-1.8）=1
0.6x+8-x+9=1
-0.4x=-16
x=40