There is a batch of coal in the factory. It is planned to burn 6 tons a day, which can burn 80 days. In fact, it saves 20% every day compared with the original plan. How many days did this batch of coal actually burn?

There is a batch of coal in the factory. It is planned to burn 6 tons a day, which can burn 80 days. In fact, it saves 20% every day compared with the original plan. How many days did this batch of coal actually burn?


The actual days of burning this batch of coal: 6 × 80 ^ [6 × (1-20%)], = 6 × 80 ^ 4.8, = 480 ^ 4.8, = 100 (days); a: this batch of coal can actually be burned for 100 days



How to solve the equation 3x + 9 = 271


3X+9=271
3X=262
x=262/3
Hope to help you (^ o ^)/~



If the solution of the equation 3x + 3 = x + 9 about X is 4 less than that of 3ax-12 = 0, find the value of A


3x + 3 = x + 9
3x - x = 9 - 3
2x = 6
x = 3
3ax - 12 = 0
3ax = 12
x = 4/a
So 3 + 4 = 4 / A
4/a = 7
a = 4/7



3x + 9 = 45 to solve the equation


3x+9=45
3x=45-9
3x=36
x=36÷3
x=12



The solution of the square of (x + 3x) - 2 (x + 3) - 8 = 0


(x^2+3x)^2-2(x^3+3x)-8=0
(x^2+3x-4).(x^2+3x+2)=0
(x+4)(x-1)(x+1)(x+2) =0



How to solve the problem that the square of 3x plus five x equals 0
It's a quadratic equation of one variable under eight


(3x)2+5x=0
x1=0
x2=-5/3



Given the quadratic function y = xsquare-3x-10, the intersection coordinates of the parabola image and the coordinate axis are obtained
Find the distance between the intersection of parabola and X-axis


In y = x ^ 2-3x-10, let x = 0, then y = - 10, the intersection of parabola and y-axis is (0, - 10). Let y = 0, then x ^ 2-3x-10 = 0, x + 2 (X-5) = 0, x = - 2 or 5, that is, the intersection of parabola and x-axis is (- 2,0) and (5,0). The distance between parabola and x-axis is: | 5 -



The image of quadratic function y = - x square + 3x-4 is a straight parabola. The focal coordinates and quasi equation of this parabola are obtained


Vertex coordinates!
Y = - x square + 3x-4
Y = - (x-3 / 2) square-7 / 4
(3/2,-7/4)
Equation: x-3 / 2 = 0



-The cube of (- 2 / 3x cube, y squared)
-The cube of (- 2 / 3x cube, y squared)
The cube of (- x to the power of M + 1)
-8 to the power of 2012 * (- 0.125) to the power of 2013


-(-3/2x^3y^2)^3
=-(-27/8x^9y^6)
=27/8x^9y^6
[-x^(m+1)]^3
=-x^[3(m+1)]
=-x^(3m+3)
-8^2012*(-0.125)^2013
=-8^2012*(-0.125)^2012*(-0.125)
=-[8*(-0.125)]^2012*(-0.125)
=[-1]^2012*0.125
=1*0.125
=0.125



Graph y = | x square - 2x + 1 | image graph y = x square - 2 | x | + 1, and prove the parity graph y = | x square - 3x-4 | image


First, draw the image of quadratic function in the absolute value, and then turn up the part below the x-axis. If you want to discuss this image by classification, discuss it when it is divided into X & gt; 0 and X & lt; 0, and then draw the map separately, and integrate the final image according to the definition field