How to solve several equation problems in junior high school? Rewrite the equation to express y with the formula containing X! I don't want answers. I want answers （1）3/2x+2y=1 （2）1/4x+7/4y=2 (3)5x-3y=x-2y (4)3(3y-3)=6x+4

How to solve several equation problems in junior high school? Rewrite the equation to express y with the formula containing X! I don't want answers. I want answers （1）3/2x+2y=1 （2）1/4x+7/4y=2 (3)5x-3y=x-2y (4)3(3y-3)=6x+4

Question 1: first, multiply both sides by 2 to get 3x + 4Y = 2, and then move 3x to the right to get 4Y = 2-3x. At this time, as long as both sides divide by 4 to get y = 1 / 2 - (3 / 4) x, several formulas by analogy can also be shifted to get the desired formula

Solutions and answers to several mathematical equation problems
(1) A pool has three water pipes: A, B and C. A and B are water inlet pipes and C are drainage pipes. A can fill the pool after 16 minutes of opening, a can fill the pool after 10 minutes of opening, and C can drain the whole pool after 20 minutes of opening. Now open both a and B pipes at the same time for 4 minutes, then close a pipe and open C pipe, and fill the pool after a few minutes? Please list the unknowns and equations
(2) Given that x = - 4 is the solution of the equation 2x + 3|a| = X-1, find the value of A
(3) Five teachers took some students to travel (unified payment of travel expenses). They contacted two travel agencies with the same price. After negotiation, the discount offered by company a is: teachers pay in full, students pay 70% off, and the discount offered by company B is that teachers and students pay 80% off
① The two companies charge the same when there are many students
② There are 20 more students. Which company should they choose
(4) Solution equation: x x x x
——+——+——+——… + —————=2005
1×2 2×3 3×4 4×5 2005×2006
(5) It is known that the sum of the solutions of the equation 2x + 3 = x + K and x-3 = 5K about X is 6. Try to find out the value of K

(1) Let 1 △ 16 = 1 / 16, 1 △ 10 = 1 / 10, 1 △ 20 = 1 / 20, and then fill (1 / 16 + 1 / 10) × (4 + x) - 1 / 20 × x = 113 / 80 × 4 + 13 / 80 × x-x / 20 = 113 / 80x-x / 20 = 1-52 / 809 / 80x = 28 / 80x = 28 / 9 (2) 2x + 3 | a | = X-1 solution - 8 + 3 | a | = - 4-13 | a | =