According to the series equation of equivalency, a number 5 times is 2.1 more than 14.9. What is the number?

According to the series equation of equivalency, a number 5 times is 2.1 more than 14.9. What is the number?

5x-14.9=2.1
5x=17
x=3.4

Number a is 8 out of 9, which is equivalent to 5 out of 7 and 1 out of 5 in number B. what is number B? (calculated by equation.)

Let B be X
5/7X+1/5=8/9
5/7X=8/9-1/5
5/7X=31/45
X=31/45÷5/7
X=217/225

What number 4 times more than 6.7 9.3, what number

Let this number be x, then we have:
4x-6.7=9.3;
4x=16;
x=4;
The number is four;

1. 7 / 9 of a number is 5 more than 1 / 4 of 260. Find the number

Let this number be x, then
7/9·x-260·1/4=5
7/9·x-65=5
7/9·x=70
x=90
A: the number is 90
I'm glad to solve the above problems for you. I hope it will be helpful to your study

Solving the system of equations x + y = 5 {X-2} a + 2 {Y-2} = x

Because x + y = 5, x = 5-y;
(X-2) a + 2 (Y-2) = x can be reduced to (X-2) a + 2 (Y-2) = 5-y;
The deformation of the above formula is (X-2) a = - 3 (Y-3);
So, when a = 0, X is any real number, y = 3;
When a ≠ 0, x = 2, y = 3;

Solve the equations X: y = 1:5y: z = 2:3x + y + Z = 27

x: Y = 1:5 = 2:10, Y: z = 2:3 = 10:15, let x = 2K, y = 10K, z = 15K, ∵ x + y + Z = 27, ∵ 2K + 10K + 15K = 27, k = 1, ∵ x = 2, y = 10, z = 15, so the solution of the equations is x = 2Y = 10z = 15

If x and Y in the bivariate linear equation composed of 3x-3y = k, 2x + 3Y = 6 are opposite to each other, the value of K is obtained

Let y = - X. we get 3x3x = 6x = k, 2x-3x = = - x = 6, x = - 6, k = 6x = - 36

1. In the bivariate linear equation 3x + 4Y = 9, if 3Y = 6, then X=____ 2. The positive integer solution of the bivariate linear equation x + 3Y = 9 is_____ ?
3. Given that x = 1U = - 8 is a solution of the linear equation of two variables 3mx-y = - 1, then M=____ ?

1、1/3
2、（3,2）（6,1）
3. I don't understand

Bivariate linear equation 2x-3y = 6 3x-y = 4

2x-3y=6 (1)
3x-y=4 (2)
(1) 3 - (2) × 2
-9y+2y=6×3-4×2
-7y=10
y=-10/7
Substituting formula (2), we get
3x+10/7=4
x=6/7

Given that line L passes through point P (3,1) and is cut by two parallel lines L1 x + y + 1 = 0 and L2: x + y + 6 = 0, the length of line segment is 5, the equation of line L is obtained

Let L: y = KX + B (K ≠ 0) because the distance between the intersection of L1 and L1 through (3,1) ‖ 1 = 3K + BB = 1-3kl: y = KX + 1-3kl: [(3K-2) / (K + 1), (- 4K + 1) / (K + 1)] l and L2: [(3k-7) / (K + 1), (- 9K + 1) / (K + 1)] is 5:5 & sup2; = 5 & sup2; / (K + 1) & sup2; + (5K) & sup2; / (K + 1) & sup2