Given that point a is in the second quadrant, and the distance to X axis is equal to 2, and the distance to y axis is equal to 3, then the coordinate of point a is__

Given that point a is in the second quadrant, and the distance to X axis is equal to 2, and the distance to y axis is equal to 3, then the coordinate of point a is__

(-3,2)

Given that the distance from point m to x-axis is 2, the distance from point m to Y-axis is 3, and M is in the fourth quadrant, then the coordinates of points m are?

The distance from point m to the x-axis is 2
The ordinate is ± 2
The distance to the y-axis is 3
The abscissa is ± 3
∵ m is in the fourth quadrant
∴x＜0,y＜0
The coordinates of M are (- 3, - 2)

It is known that m (a-1,3a) is in the third quadrant, and its distance to the x-axis is 3 greater than that to the y-axis?
Do you need to use absolute value? If so, please explain in detail,

Need
The distance to the x-axis is the absolute value of the ordinate
The distance to the y-axis is the absolute value of the abscissa
In the third quadrant, the abscissa and ordinate are less than 0
a-1