The distance from point P (x, y) to the x-axis is_______ Then the distance of y-axis is_______ The distance to the origin is_______ .

The distance from point P (x, y) to the x-axis is_______ Then the distance of y-axis is_______ The distance to the origin is_______ .

The distance from point P (x, y) to the x-axis is__ lyl_____ Then the distance of y-axis is___ lxl____ The distance to the origin is_____ √x²+y²__ .
If you don't understand this question, you can ask,

Find a point m on the y-axis so that the distance between M and n (6,8) is equal to 10

M(0,a)
Make NP perpendicular to y axis through n
P(0,8)
So NP = 6
PM=|a-8|
From Pythagorean theorem
PM²+PN²=MN²=10²
So a & sup2; - 16A + 64 + 36 = 100
a(a-16)=0
a=0,a=16
So m (0,0) and m (0,16)

The distance from the point m (- 2.3) to the x-axis is Y-axis and the origin is y-axis

3, 2, root 13

Given that point m (3, - 2) and point m '(x, y) are on the same straight line parallel to X axis, and the distance from M' to y axis is equal to 4, then the coordinate of point m 'is ()
A. (4, 2) or (- 4, 2) B. (4, - 2) or (- 4, - 2) C. (4, - 2) or (- 5, - 2) d. (4, - 2) or (- 1, - 2)

∵ m (3, - 2) and point m '(x, y) are on the same straight line parallel to the x-axis, the ordinate of ∵ M' is y = - 2, ∵ the distance from M 'to Y-axis is 4 ", and the abscissa of ∵ M' is 4 or - 4. Therefore, the coordinate of point m 'is (4, - 2) or (- 4, - 2), so B