If there are two points m (a, b), n (a, - b) in rectangular coordinates, then these two points () A. On X-axis symmetry B. on Y-axis symmetry C. on origin symmetry D. none of the above conclusions are correct

If there are two points m (a, b), n (a, - b) in rectangular coordinates, then these two points () A. On X-axis symmetry B. on Y-axis symmetry C. on origin symmetry D. none of the above conclusions are correct

According to the property of axial symmetry, if two points m (a, b), n (a, - b) are known, then these two points are symmetric about X axis

Given the point a (A-3 / 5,2b + 2 / 3), the coordinate system is established with a as the coordinate origin
Answer the following questions:
1. Determine the value of a / b
2. Determine the coordinates of point B (2a-7 / 5,3b + 1)

As long as: A-3 / 5 = 0
If 2B + 2 / 3 = 0, a = 3 / 5, B = - 1 / 3, then a / b = - 9 / 5
B (- 1 / 5, 0) can be obtained by substituting the value of a B into the coordinate of B

If the symmetric coordinates of point P (4-A, 2a-5) with respect to origin o are (B, - 1), then the coordinates of the symmetric point of point P with respect to y axis are (B, - 1)______

If the symmetric coordinates of point P (4-A, 2a-5) with respect to origin o are (B, - 1)
So 4-A = - B, 2a-5 = 1
So a = 3, B = - 1
So p (1,1)
So the coordinates of the symmetric point P about the Y axis are (- 1,1)
If you don't understand, I wish you a happy study!

If the symmetric point of P (2a + 1,2a-1) about X axis is known to be (2a + 1,3), then a is equal to the coordinate of? Point P, which is?

A = - 1, P coordinate is (- 1, - 1)

It is known that the line y = - 3x-3 intersects with the X axis, the Y axis intersects at points a and B respectively, the point C and point a are symmetrical about the origin of coordinates, the line passing through point C intersects with the Y axis at point D, and intersects with the line AB at point e, and point E is in the third quadrant
(1) The analytic formula of ab
(2) If point d (0,1) passes through point B, make BF ⊥ CD to F, connect BC, and calculate the degree of ∠ def and the area of △ BCE

(1) Y = 3x-3 when x = 0, y = - 3 when y = 0, x = 1, so a (1,0) B (0, - 3) let AB analytic formula be y = KX + B, then 0 = K + B, - 3 + B, so B = - 3, k = 3, so AB analytic formula is y = 3x-3 (2) because C and a origin are symmetric, so C (- 1,0) d (0,1) so CD analytic formula is y = x + 1CD and ab intersect e, so x + 1 = 3x-3, solution

If point a (2m + 3,3-2n) and point B (m-1, N + 1) are symmetric about the origin, then the value of N / M is

Point a (2m + 3,3-2n) and point B (m-1, N + 1) are symmetric about the origin,
2m+3+m-1=0,3-2n+n+1=0,
m=-2/3,n=4,
∴n/m=-6.

Given that the symmetric point of point a (M + 1,2n-3) about origin o is point a '(2m + 1, - n-1), find the value of M, n

m+1+2m+1=0
2n-3-n-1=0

If point a (m-2,2n + 5) and point B (2m-7,1) are symmetric with respect to the origin, then the values of M and N are

(m-2+2m-7)/2=0
The midpoint coordinates of (2n + 5 + 1) / 2 = 0 AB are the origin (0,0)
The solution is m = 3, n = - 3

Given that point a (M + 1,2n-3) is symmetric with respect to origin o, and point A1 (2m + 1, - n-1), find the value of M and n

Because point a and A1 are symmetrical about the origin, that is, (M + 1) + (2m + 1) = 0, the solution is m = - 2 / 3 (2n-3) + (- n-1) = 0, and the solution is n = 4 / 3

If the point P (- 7, - M Square-1) in the plane rectangular coordinate system is in the third quadrant, what is the value range of M?

According to the meaning of the title: - M2-1 < 0, that is: M2 + 1 > 0,
∵m2≥0,
When M2 + 1 ＞ 0, it holds,
Ψ m is all real numbers