Given that a (a, b) and B (C, d) are symmetric about y axis, try to find the value of 3A + 3C + 2B / d

Given that a (a, b) and B (C, d) are symmetric about y axis, try to find the value of 3A + 3C + 2B / d

Because a (a, b) and B (C, d) are symmetric about the Y axis
So a = - C, B = D
So 3A + 3C + 2B / D = 3 * (a + C) + 2 * 1
=3*0+2=2

Given that the points P (a + B, 7), q (6,3a-2b) are symmetric about X axis, try to find the value of a-b
Let m (2a-3,3-a) be a symmetric point about the y-axis in the second quadrant, and a be an integer. Try to find the coordinates of a and m

Because P and Q are symmetric about X axis, x coordinates are equal, that is: a + B = 6, y coordinates are opposite to each other, that is: 3a-2b = - 7. The solution is a = 1, B = 5, so A-B = - 4

X + Y-3 = o find the intercept of the slope of the following line on the Y-axis and draw a graph

x+y-3=0
y=-x+3
Slope-1 intercept 3

4Y + 6 = 0 find the slope of the line and the intercept on the y-axis?

4y+6=0
y= -3/2
So: slope 0, intercept 3 / 2 on y-axis

Find the intercept of the line 3x-5y + 10 = 0 on the Y axis and the slope k of the line

If the slope of the intercept is calculated by the linear equation, then the form of the linear equation is written as a point oblique form
Y = KX + B, then K is the slope of the line and B is the intercept of the line on the Y axis
In this question: 3x-5y + 10 = 0 is written as: y = 3 / 5x + 2
So k = 3 / 5, B = 2

Given that a straight line passes through a point (- 2,3), and the intercept on X and Y axes is equal, the equation of the straight line is obtained

Classification
(1) Through the origin, the slope k = 3 / (- 2), and the linear equation is y = (- 3 / 2) X
(2) But at the origin, the slope is - 1
Let the line be y = - x + B
Substituting (- 2,3)
Then 3 = 2 + B
That is, B = 1
The equation is y = - x + 1
The linear equation is y = (- 3 / 2) x or y = - x + 1

Given the linear equation 3x + 2y-6 = 0, calculate the slope and longitudinal intercept of the line

3x+2y-6=0
2y=-3x+6
y=(-3/2)x+3
y=kx+b
The slope of the line k = - 3 / 2,
Longitudinal intercept B = 3;

What is the slope of equation 3x-y + 2 = 0 and the intercept on the Y axis?

The slope is 3, and the intercept on the Y axis is 2, that is, when x = 0, y = 2

Find the linear equation with the slope equal to the slope of the line 3x-2y = 0 and passing through the point (- 4,3)

The slope of the straight line 3x-2y = 0 is 3 / 2, and the straight line passes through the point (- 4,3). According to the point oblique equation of the straight line, we can write out the straight line equation: Y-3 = 3 / 2 * (x + 4), and then sort it out

Given that the slope of the line L is equal to the slope of the line 4x-y + 6 = 0, and l passes through the point P (3,4), the equation of the line L and the intercept of L on the X and Y axes are obtained

Let the equation of line l be 4x-y + B = 0
L over point P (3,4),
Then, 4 * 3-4 + B = 0
The solution is b = - 8
So the equation of line L is 4x-y-8 = 0
4x-y-8 = 0 to intercept formula:
4x-y=8
x/2+y/(-8)=1
So the intercept of L on the x-axis is 2, and the intercept on the y-axis is - 8