If the graph of a function of degree passes (0,3) and (- 4,0), a new point is determined on the x-axis so that the triangle formed by connecting the three points is an isosceles triangle Oh, by the way, these two points are not sure (I can't remember them clearly). There may be (0,4) (- 3,

If the graph of a function of degree passes (0,3) and (- 4,0), a new point is determined on the x-axis so that the triangle formed by connecting the three points is an isosceles triangle Oh, by the way, these two points are not sure (I can't remember them clearly). There may be (0,4) (- 3,

If a (0,3) B (- 4,0) determines another point on the x-axis, the triangle connected by the three points is an isosceles triangle. There are four answers. Whether the two points are right or not, I'll give you a method. If a (0,3) B (- 4,0) determines another point on the x-axis, the triangle connected by the three points is an isosceles triangle

How to find a, B and C in the secondary function chart according to junior high school mathematics
Look at the graph of quadratic function, how to judge a B C

When a > 0, the opening is upward; when A0, it intersects with the Y axis on the positive half axis;
c

Drawing method of graph of first order function
When drawing a function image, take x as 0 and 1 to find out the corresponding value of Y. when x and y have both values, we will find two coordinates, draw two points, and then connect them to draw a straight line. Is this right?

Absolutely
However, when drawing a function image [the image is a straight line], the better one can be taken as follows: when x = 0 is substituted to calculate the value of Y is Y1, and y = 0 is substituted to calculate the value of X is x1, then you can take points (0, Y1), (x1,0) on the coordinate axis, which is more convenient

If √ - A + √ 2 / AB is meaningful, which quadrant is the point P (a, b) in the plane rectangular coordinate system

From the meaning of the title:
-a≥0
ab＞0
The solution is as follows
a≤0
b＜0
So: a < 0 and B < 0
So: (a, b) in the third quadrant

What are the X and Y points of a function image and how to find them?

It is known that P (a + b) is a point in the plane rectangular coordinate system. When AB > 0, which quadrant is the point P in?

1、 Four quadrants

Given that the line y = KX + B is parallel to the line y = - 3x + 4 and passes through points (2,8), then K=_________
b=________

As long as the two lines are parallel, the coefficients before X are equal, so k = - 3, and then substituting the point (2,8), there is
8 = 2 * - 3 + B, so B = 14

In the plane rectangular coordinate system, if point P (a, b) is in the second quadrant, then point Q (1-A, - b) is in the () quadrant
A. First quadrant B. second quadrant C. third quadrant D. fourth quadrant

∵ point P (a, b) is in the second quadrant, ∵ a < 0, b > 0; ∵ - a > 0, - B < 0, then 1-A > 0, that is, point Q (1-A, - b) is in the fourth quadrant

A simple graph problem of second order function in junior high school
Given the point a (a + 2,1-a) on the graph of function y = 2x + 1, the value of a is obtained
Now I don't understand a function image at all. What should I do!

Function is the main problem is to draw the image
This point a is on the function, that is to say
A + 2 is the value of X, and 1-A is the value of Y
Take them into the analytic form of the function
That is 1-A = 2 (a + 2) + 1
Simplification:
1-a=2a+5
a=-4/3
Do more questions, slowly understand, come on!

Given that the point P (a, b) is the point of the second quadrant in the plane rectangular coordinate system, the result of simplifying | A-B | + | B-A | is ()
A. -2a+2bB. 2aC. 2a-2bD. 0

∵ point P (a, b) is the point of the second quadrant in the plane rectangular coordinate system, ∵ a ＜ 0, B ＞ 0, ∵ A-B | + | B-A | = - A + B + B-A = - 2A + 2B