The intercept of point P (2, - 1) on x-axis and y-axis is a and B respectively, which satisfies the linear equation of a = 3B

The intercept of point P (2, - 1) on x-axis and y-axis is a and B respectively, which satisfies the linear equation of a = 3B

If a = 0, the linear equation is y = - 12x; if a ≠ 0, let the linear equation be XA + Yb = 1, then a = - 1, B = - 13, and the obtained linear equation is x + 2Y = 0 or x + 3Y + 1 = 0

What is the square of 2x - 8x = - 14 x

2X squared - 8x = - 14
2(x^2-4x+7)=0
2[(x-2)^2+3]=0
The equation has no solution

The square of X + 2x + 2 = 8x + 4, the square of X - 2X-4 = 0

x^2+2x+2=8x+4
x^2-6x=2
x^2-6x+9=11
(x-3)^2=11
X = 3 + √ 11 or x = 3 - √ 11
x^2-2x-4=0
x^2-2x=4
x^2-2x+1=5
(x-1)^2=5
X = 1 + √ 5 or x = 1 - √ 5

(2x squared - 8x + 8) / (X-2)

Original formula = 2 (X & sup2; - 4x + 4) / (X-2)
=2(x-2)²/(x-2)
=2(x-2)
=2x-4

If the real number m, n satisfies (m square + n square) (m square n square - 2) - 8 = 0, find the value of m square + n square

Solution
(m²+n²)(m²+n²-2)-8=0
(m²+n²)²-2(m²+n²)-8=0
[(m²+n²)-4][(m²+n+2]=0
∵m²+n²≥0
∴m²+n²=4

In the plane rectangular coordinate system, the points whose coordinates are a (2,3) B (4,7) C (6,7) d (4,3) are connected by line segments to form a figure
(1) The ordinates of the four points remain unchanged, the abscissa becomes half of the original, and the four points are connected with line segments in turn. What is the change between the figure and the original figure?
(2) If the ordinate remains unchanged, how about adding 3 to the abscissa?
(3) If the abscissa remains unchanged, how about adding 3 to the ordinate?
(4) The abscissa remains unchanged, and the ordinate is multiplied by - 1 respectively?
(5) Do the horizontal and vertical coordinates have to be doubled?

(1) Compared with the original figure, the transverse compression of the figure is 1 / 2 times of the original figure
(2) Compared with the original figure, the shape of the figure is shifted three units to the left
(3) The shape of the figure is unchanged, and the figure is shifted up three units compared with the original figure
(4) The shape of the obtained figure remains unchanged, and the obtained figure is symmetrical with the original figure about the X axis
(5) The results show that the shape of the figure is unchanged, and the horizontal elongation of the figure and the original figure is 2 times of the original, and the longitudinal elongation is also 2 times of the original

In the plane rectangular coordinate system, the coordinates of the two ends of the line AB are a (- 1,3) B (- 3,1), and the line AB is translated down two units, and then down four units to get CD (a corresponds to s, B corresponds to c) to find the area of the triangle ABC

Two and four down? Wrong

Find a mathematical problem: in the plane rectangular coordinate system, given points a (- 1,0) and B (1,2), connect AB, translate line AB to get line A1B1
In the plane rectangular coordinate system, given points a (- 1,0) and B (1,2), connect AB and translate line AB to get line A1B1. If the coordinates of point A1 are (1, - 3), then the coordinates of point B1 are

The translation vector = (2, - 3), so the coordinates of B1 are (3, - 1)

If the point P (3a-6,2a + 5) is on the bisector of the second and fourth quadrants, then its coordinates about the y-axis symmetric point P1 are?

Because point P (3a-6,2a + 5) is on the bisector of the second and fourth quadrants
So 3a-6 + 2A + 5 = 0
So a = 1 / 5
So p (- 27 / 5,27 / 5)
So its coordinates about the y-axis symmetric point P1 are (27 / 5,27 / 5)
If you don't understand, please hi me, I wish you a happy study!

If the point P (3a-2,1 + a) is in the second quadrant with respect to the y-axis symmetric point P1, then the value range of a is?

From the problem we know that: P in a quadrant, 3a-2 > 0 and 1 + a > 0, the solution is a > 4 / 3