The equation of the line with intercept of 4 and - 3 on X and Y axes is______ ．

The equation of the line with intercept of 4 and - 3 on X and Y axes is______ ．

The equation of the line with intercept of 4 and - 3 on x-axis and y-axis is X4 + y − 3 = 1, which is changed to 3x-4y-12 = 0. So the answer is: 3x-4y-12 = 0

If a line passes through a point (5,6) and the intercept on the x-axis is twice that on the y-axis, the equation of the line is

Let the analytic formula of the straight line be: y-6 = K (X-5) and the intersection of X axis be: (5-6 / K, 0) and Y axis be: (0,6-5k), then the intercept on X axis is: 5-6 / K and the intercept on Y axis is: 6-5k. Because the intercept on X axis is twice that on Y axis, so 5-6 / k = 2 (6-5k) 5-6 / k = 12-10k, the solution is: k = - 1 / 2 or K = 6

The intercept on the y-axis is l, and the linear equation parallel to the x-axis is?
Is the answer y = ± 1?
Is there a difference between positive and negative intercept?

No
Intercept signed
So y = 1
Y = - 1 and the intercept is - 1

Find the linear equation with intercept - 3 on X axis and parallel to y axis
Write the equation of the line according to the following conditions and turn it into a general formula

The form of the line parallel to the Y axis is x = a
If the intercept on the X axis is - 3, then a = - 3
So the linear equation is: x = - 3
This kind of linearization is not general