The distance from the center of circle (x-1) 2 + y2 = 1 to the straight line y = 33x is () A. 12B. 32C. 1D. 3

The distance from the center of circle (x-1) 2 + y2 = 1 to the straight line y = 33x is () A. 12B. 32C. 1D. 3

From (x-1) 2 + y2 = 1, we can get the center of the circle (1, 0), so according to the distance formula from the point to the straight line, we can get d = | 33 | (33) 2 + (− 1) 2 = 33233 = 12

In the quadratic function y = a (X-H) ^ 2 + K, the axis of symmetry, vertex coordinates and extremum are expressed in letters

The axis of symmetry is a straight line x = H
The vertex coordinates are (h, K)
The extreme value is K

The vertex form of quadratic function y = the square of AX + the square of BX + C?

y=a[x+b/(2a)]+(b^2-4ac)/(4a)

What is the square of the absolute value of 3-pie plus the root (4-pie)

π is about 3.14
three