An aluminum can make a cube frame with an edge length of 8cm. If you make a cuboid frame with aluminum of 10cm long and 9cm wide, how high is the cuboid? Is the cuboid equal to the cuboid in volume?

An aluminum can make a cube frame with an edge length of 8cm. If you make a cuboid frame with aluminum of 10cm long and 9cm wide, how high is the cuboid? Is the cuboid equal to the cuboid in volume?


8×12÷4-(10+9)=5
Answer: the height is 5cm, the volume is not necessarily equal



A 12cm long, 8cm wide and 5cm high rectangular aluminum ingot is fused with another 3cm long cube aluminum ingot to form a rectangular aluminum block. The side length of the bottom surface of the fused rectangle is 13cm. What is the height?


H=(12*8*5+3*3*3)/13/13=3cm



A wire can make a cuboid frame of 7cm long, 6cm wide and 5cm high. If we use this wire to make a maximum cube frame
What is the edge length of this cube?


(7+6+5)*4/12、
=18*4/12、
=6 cm



Find the area of the triangle enclosed by the image y = 2x + 3, y = - x + 5 and X axis of a function of degree


The intersection points of y = 2x + 3 and y = - x + 5 (2 / 3,13 / 3)
The ordinate of the focus is the height of the triangle
Y = 2x + 3 intersection X-axis at (- 3 / 2,0)
Y = - x + 5 intersects X axis at (5,0)
So the base length of triangle is 5 - (- 3 / 2) = 13 / 2
Triangle area = 1 / 2 × 13 / 2 × 13 / 3 = 169 / 12



Draw an image of a function y = - 2x + 2, and write out the intersection coordinates of the function image and the x-axis and y-axis


(0.2) (1.0)



Draw an image of the function y = - 2X-4 in rectangular coordinate system and answer the following questions. 1. What is the coordinate of the intersection of the image with X axis and Y axis?
What is the distance between the two points? ② when x takes what value, Y > 0; when x takes what value, y < 0; ③ what is the area of the triangle formed by the image and the two coordinates


1、(-2,0)、(0,-4)
2、X0;X



Draw the image of the following function and point out the abscissa of the intersection of the image and the X axis. Y = - 2x (x-4) y = (x + 2) (x-3)
Just give me a table. The main thing is that you can't find the vertices


The vertex coordinates of y = - 2x (x-4) are (2,8)
The vertex coordinates of y = (x + 2) (x-3) are (- 2,3)



The coordinate of the intersection of the image of the first-order function y = - 2x + 4 and the x-axis is______ .


Let y = 0, then y = - 2x + 4 = 0, the solution is: x = 2, so the coordinates of the intersection of the image and X axis are (2,0)



What are the coordinates of the intersection of the image of a linear function y = 2x-6 and the X axis, and what are the coordinates of the intersection of the image and the Y axis?


Let x = 0, then y = - 6
Let y = 0
Then 0 = 2x-6
2x=6
x=3
So the coordinates of the intersection point with the X axis are (3,0)
The coordinates of the intersection point with y axis are (0, - 6)



The number of focal points of the image of function y = f (x) and the line x = a in the same coordinate system


There is only one intersection, which is determined by the definition of function: an independent variable corresponds to a unique function value, that is, an X corresponds to a unique y
The line x = a has been determined. To intersect with the line, then the X of the function y = f (x) is determined. It must also be a. according to the previous work, y is uniquely determined, so there can only be one intersection point