Put the test charge of the negative ninth power of Q1 = - 1 × 10 into the electric field P generated by the point charge Q, and the electric field force of Q1 is measured to be the negative sixth power of 1 times 10 If Q1 is removed and a point charge Q2 = 2 times 10 to the power of minus 8 is placed at P point, then the electric field force on Q2 is? What is the electric field strength generated by Q at P point? Direction?

Put the test charge of the negative ninth power of Q1 = - 1 × 10 into the electric field P generated by the point charge Q, and the electric field force of Q1 is measured to be the negative sixth power of 1 times 10 If Q1 is removed and a point charge Q2 = 2 times 10 to the power of minus 8 is placed at P point, then the electric field force on Q2 is? What is the electric field strength generated by Q at P point? Direction?

Analysis:
(1) E = f / Q = 10, the direction is horizontal to the right
(2) F2 = eq2 = 2 times the negative 5th power of 10, horizontally to the left

At point P in an electric field, put a test charge with charge Q1 = - 3.0 × 10-10c, and the electric field force on the charge is measured to be F1 = 6.0 × 10-7n, horizontally to the right
(1) The magnitude and direction of the electric field at P point
(2) Put a test charge with charge quantity of Q2 = 1.0 × 10-10c at point P, and calculate the magnitude and direction of electric field force F2 on Q2
(3) The size and direction of electric field strength when P point is not put to test charge

A plus sign means horizontal to the right
F = EQ, bring in the sign, you can calculate. The final e is negative, the direction is left
The second question, or into the sign calculation, the final result of F2 is negative, the direction of horizontal left
The third question, the answer is exactly the same as the first question. The field strength has nothing to do with the test charge

The electric quantity of the two point charges is - 9 power * C of Q1 = 4 * 10 and - 9 power × C of Q2 = - 9 * 10 respectively
On two points a and B 20cm apart, to make a point charge at a certain point just can be stationary, find the position of this point?

I think it seems that the answer is two
Make a system of equations with the formula you just learned

At point P in an electric field, put a test charge with charge quantity Q1 = - 3.0 × 10-10c, and the electric field force on the charge is measured to be F1 = 6.0 × 10-7n, square
A test charge with charge Q1 = - 3.0 × 10-10c is placed at point P in an electric field. The electric field force on the charge is measured to be F1 = 6.0 × 10-7n, and the direction is horizontal to the right. Ask for:
(1) The magnitude and direction of the electric field at P point
(2) Put a test charge with charge quantity of Q2 = 1.0 × 10-10c at point P, and calculate the magnitude and direction of electric field force F2 on Q2
(3) The size and direction of electric field strength when P point is not put to test charge

(1) 2.0 × 10 ^ 3N / C; direction left
(2) 2.0 × 10 ^ 7n; direction left
(3) 2.0 × 10 ^ 3N / C; direction left