Calculation: (- 1 / 2x ^ 2Y) ^ 3 · (- 3xy ^ 2) ^ 2

Calculation: (- 1 / 2x ^ 2Y) ^ 3 · (- 3xy ^ 2) ^ 2

(-1/2x^2y)^3·(-3xy^2)^2
=(-1/8x^6y^3)·(9x²y^4)
=-9/8x^8y^7

Calculation: (x ^ 2Y) ^ 2 * (- 3xy ^ 3) * (- 6x ^ 2Y ^ 4)

:（x^2y）^2*（-3xy^3）*（-6x^2y^4）
=x^4y²×18x³y^7
=18x^7y^9

Calculation: 3xy (2x ^ 2y-1 / 3xy ^ 2)

6yx^(2y+1)-1/y

Given x + y = 3, X2 + y2-3xy = 4. Find the value of the following formula: (1) XY; & nbsp; & nbsp; (2) x3y + XY3

(1) ∵ x + y = 3, ∵ (x + y) 2 = 9, ∵ x2 + Y2 + 2XY = 9, ∵ x2 + y2 = 9-2xy, substituting x2 + y2-3xy = 4, ∵ 9-2xy-3xy = 4, the solution is xy = 1. (2) ∵ x2 + y2-3xy = 4, xy = 1, ∵ x2 + y2 = 7, and ∵ x3y + XY3 = XY (x2 + Y2), ∵ x3y + XY3 = 1 × 7 = 7