The solution of the inequality 2x & sup2; - 5ax-3a < 0 about X Given the quadratic function f (x) = ax & # 178; + BX + C, (1) if a > b > C, it is proved that the image of F (x) has two different intersections with X axis; (2) under the condition of (1), let two intersections be a and B, and find the length of line ab

The solution of the inequality 2x & sup2; - 5ax-3a < 0 about X Given the quadratic function f (x) = ax & # 178; + BX + C, (1) if a > b > C, it is proved that the image of F (x) has two different intersections with X axis; (2) under the condition of (1), let two intersections be a and B, and find the length of line ab

Because when (2x + a) (x-3a) 0 - A / 2 < x

-3a^n(a^n-1+2a^n-2+3a^n-3)+a^n-2(a^n-1-a^n+4a^n+1)
Super challenging factorization! Which genius can help me? I can make it, but I feel the answer is wrong. Ask for advice!

-3a^n(a^n-1+2a^n-2+3a^n-3)+a^n-2(a^n-1-a^n+4a^n+1)
=a^(n-2)[-3a^2(a^(n-1)+2a^(n-2)+3a^(n-3))+(a^(n-1)-a^n+4a^(n+1))]
=a^(n-2)[-3a^(n-1)(a^2+2a+3)+a^(n-1)(1-a+4a^2)]
=a^(2n-3)[-3(a^2+2a+3)+(1-a+4a^2)]
=a^(2n-3)(a^2-7a-8)
=a^(2n-3)(a+1)(a-8)

3a×（－3ab）－a（ab－2a）

=3a×9ab－a4b＋2a
=27a4b-a4b+2a
=26a^4b+2a

Simplified evaluation: (a-3b) 2 + (3a + b) 2 - (a + 5b) 2 + (a-5b) 2, where a = - 8, B = - 6

The original formula = (a-3b) 2 + (3a + b) 2 - (a + 5b) 2 + (a-5b) 2 = a2-6ab + 9b2 + 9A2 + 6ab + b2-a2-10ab-25b2 + a2-10ab + 25b2 = 10a2-20ab + 10b2 = 10 (a-b) 2, when a = - 8, B = - 6, the original formula = 10 × [(- 8) - (- 6)] 2 = 10 × (- 2) 2 = 40

Simplification: (a-3b) ^ 2 + (3a + b) ^ 2 - (a + 5b) ^ 2 + (a-5b) ^ 2
Can factorization be used?

Given x + y = 3, 3a-5b = - 4, find the value of the algebraic formula (2x + 9a) + [- (15b-2y)]

It is known that x + y = 3, 3a-5b = - 4
So:
x=3-y
3a=4+5b
So:
(2X+9a)+[-(15b-2y)]
= 6-2y+12+15b-15b+2y
= 18

If | a | = 5, | B | = 4, and | a + B | = a + B, find the value of 3a-5b

From the meaning of the title:
a+b＞0
That is: a = 5, B = 4
Or a = 5, B = - 4
1. When a = 5, B = 4,
simple form
=15-20
=-5
2. When a = 5, B = - 4,
simple form
=15+20
=35

9a2+（______） +25b2=（3a-5b）2

(3a-5b) 2 = 9a2-30ab + 25b2, so the answer is: - 30ab

If 4 / 3A = 4 / 5b, then a: B=

4/3a=4/5b,a/b=(4/5)/(4/3)=(4/5)*(3/4)=3/5

Given (3a + 5b) / b = 7 / 3, find the value of a / b
As the title!

Cross multiplication
The results are as follows
7b=3(3a+5b)
7b=9a+15b
7b-15b=9a+15b-15b
-8b=9a
So a / b = - 8 / 9