Let p be a point in Δ ABC, and vector AP = (x-2y) vector AB + (Y-1) vector AC, then the value range of X is--- The value range of Y is-----

Let p be a point in Δ ABC, and vector AP = (x-2y) vector AB + (Y-1) vector AC, then the value range of X is--- The value range of Y is-----


A point in the triangle ABC, and the vector AP = (x-2y) vector AB + (Y-1) vector AC,
When p is on BC, (x-2y) + (Y-1) = 1,
Because P is in the triangle ABC
∴0



If P is any point inside the triangle ABC, and AP vector = XAB vector + YAC vector, then the value range of X + y is


Extend AP to BC at d point
Then AP = sad, 0

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