As shown in the figure, in the rectangular coordinate system a (0,1) B (2.0) C (2,1.5) (1) find the area of △ ABC. (2) if there is a point P (a, 1 / 2) in the second quadrant Using the formula containing a to express the area of a quadrilateral abop (3) Under the condition of (2), is there a point P such that the area of the quadrilateral abop is equal to the area of △ ABC? If so, find out the coordinates of point P. if not, explain the reason

As shown in the figure, in the rectangular coordinate system a (0,1) B (2.0) C (2,1.5) (1) find the area of △ ABC. (2) if there is a point P (a, 1 / 2) in the second quadrant Using the formula containing a to express the area of a quadrilateral abop (3) Under the condition of (2), is there a point P such that the area of the quadrilateral abop is equal to the area of △ ABC? If so, find out the coordinates of point P. if not, explain the reason

1. The area of △ ABC is s = 1.5 * 2 / 2 = 1.5
2. Area of quadrangle abop = △ AOB + AOP = 2 * 1 / 2 + 1 * (- a) / 2 = 1-A / 2
3. Suppose that there exists, then 1.5 = 1-A / 2, and a = - 1. Therefore, there exists a point P whose coordinates are (- 1,1 / 2)

What's the area of a right triangle with a base angle of 45 degrees and a right side of 8 cm

32 ah. Because the base angle is 45 degrees, it is an isosceles right triangle. So its two right sides are 8cm, so s = 1 / 2Ab = 1 / 2 * 8 * 8 = 32 square cm. The one upstairs is wrong

It is known that the two right sides of a right triangle are 2m. 2m. 1 respectively. How long is the hypotenuse

Right triangle, right side is 5.05 meters and 2 meters, hypotenuse is 5.4 meters, what are the corresponding two angles

Sina = 5.05 / 5.4 = 0935, so ∠ a = 69 degree
SINB = 2 / 5.4 = 0.3704, so ∠ B = 21 °