If there is a right triangle green space, the length of two right angles is 6 m and 8 m respectively. Now we need to expand the green space into an isosceles triangle, and the expansion part is a right triangle with 8 m as the right angle side. Find the perimeter of the expanded isosceles triangle green space. (Fig. 2, Fig. 3 for standby)

If there is a right triangle green space, the length of two right angles is 6 m and 8 m respectively. Now we need to expand the green space into an isosceles triangle, and the expansion part is a right triangle with 8 m as the right angle side. Find the perimeter of the expanded isosceles triangle green space. (Fig. 2, Fig. 3 for standby)

In RT △ ABC, ∠ ACB = 90 °, AC = 8, BC = 6. According to Pythagorean theorem, there are: ab = 10, which can be divided into the following three cases: ① as shown in Figure 1, when AB = ad = 10, ≁ AC ⊥ BD, ≁ CD = CB = 6m, ≁ abd perimeter = 10 + 10 + 2 × 6 = 32m. ② as shown in Figure 2, when AB = BD = 10, ≁ BC = 6m, ≁ CD = 10-6 = 4m, ≁ ad =

There is a green space with a right triangle. The length of two right sides is 6m and 8m respectively. The green space is expanded into an isosceles right triangle, and the expanded part is a right triangle with a right side of 8m
The answer is 32 meters or 20 + 4 root 5 or 80 / 3

Choose 32
If the sum of two sides of ∵ △ is greater than the third side, that is, one side is 8, and one side is greater than 6, then the third side must be greater than 6 and 8
The circumference of this △ must be greater than or equal to 23, and 20 + 4 radical 5 and 80 / 3 are less than 23, so only 32 is in line with the meaning of the question!

The two straight sides of a right triangle are 3 and 4. The hypotenuse is 5

90\60\30