As shown in the figure, in the rectangular coordinate system, there is a right triangle OAB, and ab = 5, OA = 3, OB = 4,

A (0,3), B (4,0), three points c, C1 (- 4,0), C (- 1,0), C3
(9,0)

If the ratio of the two right sides of a right triangle is 1:2 and the hypotenuse is 5cm, the shorter right side is 5cm

Root 5cm

If the central line length of the hypotenuse of a right triangle whose perimeter is 2 + square root 6 is known to be 1, the area of the triangle can be calculated

I can't find the sign of the square root. The sign of the square makes the formula longer and more complicated. Please forgive me
Let a, B, C be the side length of a right triangle, C be the oblique side length, and the area be s
Because the center line of the hypotenuse of a right triangle is half the length of the hypotenuse of a right triangle
So C = 2
A + B + C = perimeter = 2 + square root 6
A + B = square root 6
The square of (a + b) = the square of a + the square of B + 2Ab
Square of a + square of B = square of C
So the square of (a + b) - the square of C = 2Ab
S = AB / 2 = [(a + b) square - C square] / 4 = (6-4) / 4 = 1 / 2
So it's half the area
Because there is no formula editor

In △ ABC, the vertical bisector of ∠ C = 90 °, B = 15 ° and ab is called BC at e.db = 10cm, then how much is AC?

5 (radical 6-radical 2)

As shown in the figure, in △ ABC, the vertical bisector of AB intersects BC at D and ab at E. if DB = 10cm, then AC=______ cm．

The vertical bisector connecting AD and ∵ AB intersects BC at D and ab at e ∵ ad = BD = 10, ∵ DBA = ∵ bad = 15 °, ∵ DAC = 60 °, ∵ ADC = 30 °, ∵ AC = 12ad = 5cm

In △ ABC, the vertical bisector of AB intersects BC at D, AB at e, DB = 12, then AC =?
This is the question in unit 5 axisymmetric (15.15.2)

Because DM is the vertical bisector of ab
So BD = ad
Because the angle B = 15 degrees
So the angle bad = 15 degrees
And because the angle c = 90 ° and the angle BAC = 75 °
So the angle DAC = 60 degrees
So AC = 4

In the triangle ABC, angle c = 90, angle a = 75, the vertical bisector ab of AB intersects point D, BC intersects point E, be = 16cm

AC = 8cm, AE = be, 2Ac = AE

The lengths of the two sides of a right triangle are 6 cm and 8 cm respectively, and the length of the hypotenuse is 10 cm. If the right side of 8 cm is taken as the axis to rotate the triangle for one circle
The height of the cone is () cm, the radius of the bottom is () cm, and the volume is () cubic cm

The lengths of the two sides of a right triangle are 6cm and 8cm respectively, and the length of the hypotenuse is 10cm. If the right side of 8cm is taken as the axis to rotate the triangle for one circle, a cone will be obtained. The height of the cone is (8cm), the bottom radius is (6cm), and the volume is (301.44cm3)

The three sides of a right triangle are 8 cm, 6 cm and 10 cm respectively. Now, with its longest side as the axis, what is the volume
emergency
fast

Let the height of the longest side be H8 * 6 / 2 = 10 * H / 2H = 4.8, and rotate the longest side (10cm) as an axis for one circle. Two cones with a radius of 4.8cm and a height of 10cm are obtained. Let the height be H1 and H2 respectively, and H1 + h2 = 10cm. Then, the volume of rotating one circle with the longest side as an axis is v = 1 / 3 * (3.14 * 4

The three sides of a right triangle are 10 cm, 8 cm and 6 cm respectively. A cone can be obtained by rotating around the hypotenuse axis. How many cm are the diameter and height of the bottom

The diameter of the bottom is 9.6 and the height is 10

As shown in the figure, in the rectangular coordinate system, there is a right triangle OAB, and ab = 5, OA = 3, OB = 4,