Solving right triangle At the same time, ship a and ship B depart from port a to island B. ship a sails to Island b 60 ° north by west at a speed of 10 knots; ship B sails at a speed of 20 knots, first sailing due east for 1 hour, then arriving at port C to pick up passengers. After staying for half an hour, ship a turns northeast to island B. the speed is still 20 knots There is a lighthouse on Island b, which can be seen within 5 nautical miles of the lighthouse. Ask which ship a or B sees the lighthouse first, and what is the time difference between the two ships? (accurate to minutes, √ 3 = 1.73, √ 2 = 1.41, √ 6 = 2.45)

Original title: A and B set out from port a to island B at the same time. A sailed to Island b 60 ° north by east at a speed of 15 nautical miles per hour; B sailed along due east for one hour, then arrived at port C to pick up passengers, stayed for half an hour, and then turned northeast to island B. the speed was still

Given a corner on one side, how to solve a right triangle

First, the situation
Angle Θ and right angle side: sin Θ = right angle side / hypotenuse, another right angle side and hypotenuse can be obtained
Angle Θ and hypotenuse: sin Θ = right angle side / hypotenuse, right angle side can be obtained, and then Pythagorean theorem, that is, solution

If both sides of angle A and angle B are parallel, and angle a is 30 degrees less than 2 times of angle B, then the degree of angle B is? I want to figure

Because angle A and angle B are parallel, angle a = angle c, and angle c and angle B complement each other. So angle A and angle B complement each other
Let angle B be x and angle a be 2x-30
X+2X-30=180
3X=210
X=70
Angle B = 70 degrees

If angle a is parallel to both sides of angle B, and angle a is 30 degrees less than twice of angle B, what is the degree of angle B

There are two cases when the two sides of the two corners are parallel
(1) In this case, the degree of ∠ B is set as X
2X-X=30,X=30
(2) In this case, the degree of ∠ B is set as X
2X-30=180-X
3X=210
X=70

If both sides of angle A and angle B are parallel, and angle a is 30 degrees less than twice of angle B, then the degree of angle B is as follows:

70 degrees. Let angle B be x degrees, then angle a is 2x-30 degrees
2x-30+x=180
x=70
So angle B = 70 degrees

If both sides of angle a are perpendicular to both sides of angle B, and angle a is 30 ° less than twice of angle B, calculate the degree of angle A and angle B

The two sides of angle a are perpendicular to the two sides of angle B, so a + B = 180 degrees
A = 2b-30 degrees
The solution is a = 110 degree, B = 70 degree

As shown in the figure, angle a = 30 degrees, find the degree of angle B + angle c + angle D + angle E

If both sides of a are parallel to both sides of B, and a is 20 degrees less than 3 of B, what is the difference between the degrees of the two angles?

A + B = 180 degrees, a = 3B + 20 degrees
A = 140 degrees, B = 40 degrees

If both sides of angle a are perpendicular to both sides of angle B, and angle a = 70 degrees, then what is the degree of angle B?

If both sides of angle a are perpendicular to both sides of angle B, there are two cases
1. Angle a = angle B = 70
2. If angle a + angle B = 180, then angle B = 110 degrees
You can see it by drawing a picture

In a right triangle, the lengths of the two right sides are 12 meters and 3.6 meters respectively. Find the length of the hypotenuse and the degree of the minimum acute angle

Length of hypotenuse = √ (12 × 12 + 3.6 × 3.6) = √ 156.96
Angle of minimum acute angle = arc Tan (3.6 / 12) = arc Tan 0.3