It is known that the isosceles triangle ABC is inscribed on the circle O with radius 5. If the length of the bottom edge BC is 6, then the tangent of the bottom angle is 0

It is known that the isosceles triangle ABC is inscribed on the circle O with radius 5. If the length of the bottom edge BC is 6, then the tangent of the bottom angle is 0

Let AB = AC, BC = 6
If the vertical line through point a is the bottom BC, ad = 9 or 1
Tanb = 3 or 1 / 3
Note that triangle ABC may be an obtuse triangle!

If the isosceles triangle ABC is inscribed on the circle O with radius 5 and the bottom edge BC = 8, then the area of the triangle ABC is? How to draw the figure?

If the isosceles △ ABC is inscribed in ⊙ o with radius 5 and the bottom edge is 6, then the area of △ ABC is______ ．

If the center O is in the interior of △ ABC, as shown in figure (1), ab = AC, BC = 6, and make OD ⊥ BC in D, then BD = CD = 3, ∵ AB = AC, ∵ point a is on the straight line ad, in RT △ OBD, ob = 5, BD = 3, ∵ od = ob2 − BD2 = 4, ∵ ad = 5 + 4 = 9, ∵ s △ ABC = 12 × 9 × 6 = 27; if the center O is outside of △ ABC, as shown in figure (2), and (1), OD = 4 can be calculated, then ad = 5-4 = 1, ∵ s △ ABC = 12 × 1 × 6 = 3 Or 27

If the isosceles △ ABC is inscribed in ⊙ o with radius 5 and the bottom edge is 6, then the area of △ ABC is______ ．

If the center O is in the interior of △ ABC, as shown in figure (1), ab = AC, BC = 6, and make OD ⊥ BC in D, then BD = CD = 3, ∵ AB = AC, ∵ point a is on the straight line ad, in RT △ OBD, ob = 5, BD = 3, ∵ od = ob2 − BD2 = 4, ∵ ad = 5 + 4 = 9, ∵ s △ ABC = 12 × 9 × 6 = 27; if the center O is in the exterior of △ ABC, as shown in figure (?)