As shown in the figure, the straight line AB; CD intersects at the point O, OE, bisecting the angle AOC, and the angle BOC - ∠ BOD = 18 ° to find the degree of ∠ BOE

As shown in the figure, the straight line AB; CD intersects at the point O, OE, bisecting the angle AOC, and the angle BOC - ∠ BOD = 18 ° to find the degree of ∠ BOE

∫ BOC - BOD = 18 ∫ BOC = 18 + ∫ BOD ∫ straight line CD ∫ BOC + ∫ BOD = 180 ∫ 18 + ∫ BOD + ∫ BOD = 180 ∫ AOC and ∫ BOD are opposite vertex angle ∫ AOC = ∫ BOD = 81 ∫ OE bisection ∫ AOC ∫ AOE = ∫ AOC / 2 = 40.5 ∫ straight line ab ∫ AOE + ∫ BOE = 180 ∫ BOE

It is known that: as shown in the figure, the intersection of lines AB, CD and O, OE bisects ∠ BOD;
(2) If ∠ BOC: ∠ AOC = 5:4, calculate ∠ COE degree

∵ OE bisecting ∠ BOD, ∠ BOE = 30 °
∴∠bod=2∠boe=60°
∠aoc=∠bod=60°
∠boc=180°-∠aoc=120°
∵∠boc:∠aoc=5:4,∠boc:∠aoc=180°
∴∠aoc=180°*5/(4+5)=80°
∠boc=180°-∠aoc=100°
∠bod=∠aoc=80°
∠boe=1/2∠bod=40°
∠coe=∠boc+∠boe=140°

As shown in the figure, the straight lines AB and CD intersect at point O, OE bisector angle AOC, ∠ BOC = ∠ AOD = 20 ° and calculate the degree of ∠ BOE
The picture is: a flat fork, standing down on the top of the fork, the middle point is 0, a, e, C
O
D B
The fork is AOB cod. EO

∵ straight line ab
∴∠AOB＝180
∵∠BOC＝20
∴∠AOC＝∠AOB-∠BOC＝180-20＝160
∵ OE bisection ∠ AOC
∴∠COE＝∠AOC/2＝160/2＝80
∴∠BOE＝∠BOC+∠COE＝80+20＝100

As shown in the figure, it is known that OC is the bisector of the angle AOD, OE is the bisector of the angle AOC, OA is the bisector of the angle BOE, and the angle BOC = 60 ° to calculate the degree of the angle BOD

What about the graph? I made it according to my own graph. From the known angle, boa = angle AOE = angle COE = 1 / 3, angle BOC = 20 degrees, angle AOD = angle AOC + angle cod, angle AOC = angle cod = angle AOE + angle COE = 40 degrees, angle AOD = 80 degrees, angle BOD = angle boa + angle AOD = 100 degrees