As shown in the figure, it is known that OE is the bisector of ∠ AOB, and C is a point in ∠ AOE. If ∠ BOC = 2 ∠ AOC, ∠ AOB = 114 °, calculate the degree of ∠ BOC. ∠ EOC

As shown in the figure, it is known that OE is the bisector of ∠ AOB, and C is a point in ∠ AOE. If ∠ BOC = 2 ∠ AOC, ∠ AOB = 114 °, calculate the degree of ∠ BOC. ∠ EOC

∠ BOC = 114 × 23 = 76 ° (2 points) ∠ BOE = 57 ° (2 points) ∠ EOC = ∠ BOC - ∠ BOE = 19 ° (2 points)

As shown in the figure, it is known that OE is the bisector of ∠ AOB, and C is a point in ∠ AOE. If ∠ BOC = 2 ∠ AOC, ∠ AOB = 114 °, calculate the degree of ∠ BOC. ∠ EOC

∠ BOC = 114 × 23 = 76 ° (2 points) ∠ BOE = 57 ° (2 points) ∠ EOC = ∠ BOC - ∠ BOE = 19 ° (2 points)

As shown in the figure, it is known that OE is the bisector of ∠ AOB, and C is a point in ∠ AOE. If ∠ BOC = 2 ∠ AOC, ∠ AOB = 114 °, calculate the degree of ∠ BOC. ∠ EOC

∠ BOC = 114 × 23 = 76 ° (2 points) ∠ BOE = 57 ° (2 points) ∠ EOC = ∠ BOC - ∠ BOE = 19 ° (2 points)

As shown in the figure, lines AB and CD intersect at points o, OE and of, which are bisectors of angle AOC and angle AOD respectively. Given the angle BOC = 70 degrees, calculate the degrees of angle DOF and angle Coe
Because, so answer!

∵ the line AB and CD intersect at o
∴∠AOB=∠DOC=180°
∵∠BOC=70°
∴∠AOC=180°-∠BOC=110°
∴∠AOD=180°-∠AOC=70°
∵ OE bisection ∠ AOC, of bisection ∠ AOD
∴∠COE=∠AOE=1/2∠AOC=55°
∠DOF=∠AOF=1/2∠AOD=35°