Given that the parabola y = - x2 + 2 (k-1) x + K + 2 intersects with the X axis and two points AB, and point a is on the negative half axis of the X axis, B is on the positive half axis of the X axis, Bo = 5ao, find the parabola

Given that the parabola y = - x2 + 2 (k-1) x + K + 2 intersects with the X axis and two points AB, and point a is on the negative half axis of the X axis, B is on the positive half axis of the X axis, Bo = 5ao, find the parabola

Y = - x2 + 2 (k-1) x + K + 2 intersects the X axis with two points AB, so the Y coordinate of two points AB = 0; from Bo = 5ao, let Ao be a, then point a is (- A, O) B (5a, 0). Take these two points to the equation to calculate the coordinates of two points AB, and then the parabola can be calculated

Let the parabola y = - x2 + 2mx + 2 intersect the negative half axis of X axis at point a, the positive half axis of X axis at point B, and the Y axis at point C. (1) find the value range of M. (2) the length of nob is three times that of OA, and find the value of M

① Therefore, M can be r
② The root formula is X1 = - M ＋ M2 ＋ 2, X2 = - M － M2 ＋ 2. X1 = 3 ｜ x2. The solution is M2 = 2 / 3, and - B / 2A ＞ 0, so m = √ 6 / 3. Over