If the parabola C1: y = ax ^ 2 + BX + C and C2: y = x ^ 2-5x + 2 are symmetric with respect to point m (3.2),

If the parabola C1: y = ax ^ 2 + BX + C and C2: y = x ^ 2-5x + 2 are symmetric with respect to point m (3.2),

First, find out that the axis of symmetry of C2 is a straight line x = 5 / 4. Then, since it is symmetrical about a point, then the axis of symmetry of C1 (set as a straight line x = n,) must have n-3 = 3-5 / 4. In this way, find out the axis of symmetry of C1

It is known that parabola C1: y = 3x2, the vertex of another parabola C2 is (2,5), and the shape and size are the same as parabola C1
The answer is y = 3x2 + 12x + 17 and y = - 3x2 + 12x-7. Why do I calculate y = 3x2 + 12x + 17 and y = - 3x2 + 12x + 41?

If the shape and size are the same as the parabola C1, then a = 3 or - 3
So C2: y = 3 (X-2) ^ 2 + 5 = 3x ^ 2-12x + 17 or y = - 3 (X-2) ^ 2 + 5 = - 3x ^ 2 + 12x-7

Given that the parabola y = AX2 + BX + C passes through (- 1,2) and (3,2), then the value of 4A + 2B + 3 is______ ．

Given that the parabola y = AX2 + BX + C passes through (- 1,2) and (3,2), then the value of 4A + 2B + 3 is______ ．