If the polar coordinate equation of the curve is ρ & # 178; = 400 / (16cos & # 178; θ + 25sin & # 178; θ), the general equation of the curve is?

If the polar coordinate equation of the curve is ρ & # 178; = 400 / (16cos & # 178; θ + 25sin & # 178; θ), the general equation of the curve is?

ρ & # 178; = x & # 178; + Y & # 178; Cos & # 178; θ = x & # 178; / ρ & # 178; sin & # 178; θ = y & # 178; / ρ & # 178; substituting ρ & # 178; = 400 / (16cos & # 178; θ + 25sin & # 178; θ),
We get ρ & # 178; = 400 / (16x & # 178; / ρ & # 178; + 25y & # 178; / ρ & # 178;), that is, 400 = 16x & # 178; + 25y & # 178;
That is to say, 16x & # 178 / 400 + 25y & # 178 / 400 = 1 is reduced to X & # 178 / 25 + Y & # 178 / 16 = 1
The general equation of this curve is X & # 178 / 25 + Y & # 178 / 16 = 1

The curve represented by polar coordinate equation 5 ρ Cos2 θ + ρ - 24 = 0 is?

The factorization factor p (PCOS θ 1) - 3 (PCOS θ 1) = 0 (P-3) (PCOS θ 1) = 0, so p = 3 or PCOS θ = - 1 is obviously a circle and a straight line