Divide the nine numbers 20, 26, 33, 35, 39, 42, 44, 55 and 91 into three groups to make the product of each group equal

Divide the nine numbers 20, 26, 33, 35, 39, 42, 44, 55 and 91 into three groups to make the product of each group equal

20 = 2 × 2 × 526 = 2 × 1333 = 3 × 1135 = 5 × 739 = 3 × 1342 = 2 × 3 × 744 = 2 × 2 × 1155 = 5 × 1191 = 7 × 13, there are six 2, three 3, 5, 7, 11, 13 in it. Therefore, if 20, 44, (26, 42) are separated first, then 26, 42 and 55 are exactly one group; if we look at 20, 33, 91, then 35, 44, 39 are left. That is 26 × 42 × 55 = 20 × 33 × 91 = 35 × 39 × 44

20.26.33.35.39.42.44.91.55 divided into three groups, the product is equal. Which three groups?

33,91,20
44,35,39
55,42,26

Divide 9 numbers into three groups, such as 20, 26, 33, 35, 39, 42, 44, 55 and 91, so that the opportunity of each group is equal

20.33.91
26.42.55
35.39.44
We can solve the problem by decomposing these numbers into several factors and finding out the same factors
Dizzy, I've been doing math all morning

Divide 20, 26, 33, 35, 39, 42, 44, 55 and 91 into three groups to make the product of each group equal

91 a group
44 group 2
Group 26, 42 and 55