7 * 1 / 8 + 19 / 8-2 * 0.125 7 * 1 / 8 + 19 / 8-2 * 0.125 [1.1 + 7 / (3.12-1.8)] * 1.59 2 / 15 / (7 / 4-7 / 20) * 3 / 2 7 / 6 / (2 / 5 + 1 / 2 - 1 / 8) 1 / [three quarters * (three fifths - two fifths)]

7 * 1 / 8 + 19 / 8-2 * 0.125 7 * 1 / 8 + 19 / 8-2 * 0.125 [1.1 + 7 / (3.12-1.8)] * 1.59 2 / 15 / (7 / 4-7 / 20) * 3 / 2 7 / 6 / (2 / 5 + 1 / 2 - 1 / 8) 1 / [three quarters * (three fifths - two fifths)]

7 * 1 / 8 + 19 / 8-2 * 0.125 = 7 * 1 / 8 + 19 * 1 / 8-2 * 1 / 8 = (7 + 19-2) * 1 / 8 = 24 * 1 / 8 = 3 [1.1 + 7 / (3 and 1 / 12-1 / 8)] * 1 and 1 / 59 = [1.1 + 7 / (3 + 2 / 24-1-15 / 24)] * 60 / 59 = [1.1 + 7 / (35 / 24)] * 60 / 59 = [11 / 10 + 7 * (24 / 35)] * 60 / 59

(3.19 + 3 / 3 + 6.09 + 6 / 7) * (2 / 8 minus 1.125) + (1 ／ 2 / 3 minus 1.5) * 6.2

=(3.19+6.09+10)*(2.125-1.125)+(1.5-1.5)*6.2
=19.28*1+0
=19.28

125 + (one third and one fourth) + (- one third and one eighth) + (- seven eighths) + (- 0.25) =
It is calculated by a simple method

0.125 + (third and quarter) + (- third and eighth) + (+ seven eighths) + (- 0.25)
=(0.125 + 7 / 8) + (1 / 2-0.25) - 1 / 3
=1 + 2-3 and 1 / 8
=-One in eight

(- 3 and 1 / 8) - 2.16 + 8 and 1 / 4 + 3.125-3.84-0.25
Three and one seventh x (three and one seventh - seven and one third) x seven twenty two times seven x twenty two twenty one
-370x (- quarter + 0.25x24.5 - five and half x (- 25%)

25 = (- 3.125) - 2.16 + 8 + 1 / 4 + 3.125-3.84-0.25 = (- 3.125) - 2.16 + 8.25 + 3.125-3.84-0.25 = [(- 3.125) + 3.125] - (2.16 + 3.84) + (8.25-0.25) = 0-6 + 8 = 2.3 and 1 / 7 x (3.7-1 / 7) x 7 / 22 x 22

1. - 150 * (- one eighth) - 25 * 0.125 + 50 * (- one fourth) process

= 150 * 1/8 - 25 *1/8 -50 * 1/4
= 150 *1/8 -25 *1/8 - 100 * 1/ 8
= 1/8(150-25 -100)
=25/8
Understand, give me a satisfaction, no other requirements!

-150 × (- one eighth) - 25 × 0.125 + 50 × (- one eighth)
Come on. It's coming

-150 × (- one eighth) - 25 × 0.125 + 50 × (- one eighth)
=(-1/8)×(-150+25+50)
=(-1/8)×(-75)
=75/8;
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Make an equation so that its solution is equal to 1 or - 5

The square of X + 4x-5 = 0 (Veda's theorem)

The edge length of a cube is two fifths, its surface area is () square decimeter, and its volume is () cubic meter

The edge length of a cube is two fifths, its surface area is (24 / 25) square decimeters, and its volume is (8 / 125) cubic meters
2/5x2/5x6=24/25
2/5x2/5x2/5=8/125

The edge length of a cube is two fifths of a meter, its surface area is () square meters, and its volume is () cubic meters

The edge length of a cube is two fifths of a meter, its surface area is (24 / 25) square meters, and its volume is (8 / 125) cubic meters

Solve the fractional equation. 2 divided by X + X divided by (x + 3) = 1

Multiply both sides by X (x + 3) to get:
2（x+3）+x²=x（x+3）
2x+6+x²=x²+3x
3x-2x=6
x=6
It is tested that x = 6 is the root of the original equation