Can you see from the following two figures which school has more female students? Why? School a: male: 50%, female: 50% School B: male: 60%, female: 40%

No
Did not tell the total number of the two schools. Can not know the specific figures
It is impossible to judge
Hope to adopt

The average number of students in each class in Grade 6 is 42, 16 less than that in Grade 5. How many students in each class in Grade 5

42+16=58
58/2=27

The average class size of grade 6 is 42, 16 less than that of grade 5,

（42+16）/2=29
A: there are 29 students in grade five
There are X students in the fifth grade
2x-16=42
2x=58
x=29
A: there are 29 students in grade five

There are three classes in the fifth grade of experimental primary school. There are 42 students in one class. The number of students in the second class is five sixth of that in the first class. The number of students in the third class is higher than that in the third class

Number of people Pull back

In order to make sulfur dioxide and sulfur trioxide contain the same mass of oxygen, what is the mass ratio of sulfur dioxide and sulfur trioxide
In order to make sulfur dioxide and sulfur trioxide contain the same mass of oxygen, what is the mass ratio of sulfur dioxide and sulfur trioxide? The answer is to use 48 / 80:32 / 64 to get six to five. But I reversed the two numbers and got five to six. Why use 48 / 80:32 / 64?

The proportion of oxygen in sulfur dioxide is obviously less than that in sulfur trioxide, so it must need more sulfur dioxide than sulfur trioxide
Let the mass of sulfur dioxide and sulfur trioxide be x and Y respectively, then x × 32 / 64 = y × 48 / 80 (equal mass of oxygen), and X / y = 6:5

In SO2 (sulfur dioxide) and SO3 (sulfur trioxide) with equal mass, what is the mass ratio of oxygen? What is the number ratio of oxygen atoms?

The relative molecular weight of SO2 is 64 and S03 is 80, so when the mass is equal, the mass ratio of their substances is 80:64 = 5:4, the number ratio of O atoms is 5 * 2:4 * 3 = 5:6, and the atomic weight of O atoms is the same, so the mass ratio is also 5:6

How does sulfur dioxide react with oxygen to form sulfur trioxide, and how does sulfur trioxide react with water to form sulfuric acid?

Sulfur dioxide and oxygen in the presence of a catalyst to generate sulfur trioxide: 2so2 + O2 = = catalyst 2so3, sulfur trioxide dissolved in water is sulfuric acid (sulfur trioxide easily reacts with water): SO3 + H2O = = H2SO4

How many grams of oxygen element are contained in 98 grams of sulfuric acid? How many grams of hydrogen element are contained in 98 grams of sulfuric acid? (please list the formula)

H2SO4
The molecular weight is 98 g / mol
98 g of H2SO4 is 1 mol
The O atom is 4mol
The mass is 4x16 = 64g
Let xmolh2so4 contain 4 grams of hydrogen
Hydrogen 4 g
The amount of substance is 2mol
2x=2
x=1mol
The mass of 1mol H2SO4 is 98g
Therefore, 98g H2SO4 contains 4 grams of hydrogen

How many grams of 18% and 23% sugar water are needed to prepare 1000 grams of 20% sugar water?

Let 18% x g of salt water and 23% x g of salt water (1000-x) be needed, and the result is: 18% x + 23% (1000-x) = 20% × 1000 & nbsp; & nbsp; 0.18x + 230-0.23x = 200 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.05x = 30 & nbsp; & nbsp; & nbsp

How many grams of 18% and 23% sugar water are needed to prepare 1000 grams of 20% sugar water?

Suppose 18% x + 23% (1000-x) = 20% × 1000 & nbsp; & nbsp; 0.18x + 230-0.23x = 200 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 0.05x = 30 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; if 18% x + 23% (1000-x) g of brine is needed; X = 600, 1000-600 = 400 (g) a: it needs 600 g of 18% sugar water and 400 g of 23% sugar water

Can you see from the following two figures which school has more female students? Why? School a: male: 50%, female: 50% School B: male: 60%, female: 40%