There are three groups of the same patterns: pear, peach, apple, persimmon and orange. These five patterns appear randomly, and each group only has one at a time. Only pears have the chance to appear in three groups at the same time, and other patterns can appear at most two at the same time,

Two cases
If the group has a sequence, i.e. pear peach and pear peach are different
So the total probability is 5 * 5 * 5-4 = 121
Probability is 1 / 121
On the contrary, if there is no order
Then the total probability: 5 * 4 * 3 + 5 * 4 + 1 = 81
The probability is 1 / 81

There are 200 pears, apples, oranges and persimmons. If you add 4 to the number of pears, subtract 4 from the number of apples and multiply 4 by the number of oranges, you will get the same number. How many of the four fruits are there
Using equation

Let X be equal, then the pear is x-4, the apple is x + 4, the orange is x △ 4, the persimmon is 4x, and the equation is x-4 + X + 4 + X △ 4 + 4x = 200
If x = 32, there are 28 pears, 36 apples, 8 oranges and 128 persimmons

Four kinds of fruit a total of 125, if the pear plus 4, apple minus 4, orange multiplied by 4, persimmon number divided by 4, the number of equal

The equal number is X
x-4+x+4+x/4+4x=125
x=20
Pear 20-4 = 16
Apple 20 + 4 = 24
Orange 20 △ 4 = 5
Persimmon 20 × 4 = 80

Weight of three apples + one pear = weight of 14 oranges
Weight of 6 oranges + weight of an apple = weight of a pear
The weight of a pear head = the weight of several oranges

Weight of a pear head = weight of 8 oranges

There are three groups of the same patterns: pear, peach, apple, persimmon and orange. These five patterns appear randomly, and each group only has one at a time. Only pears have the chance to appear in three groups at the same time, and other patterns can appear at most two at the same time,