The product of 12.5 and 8 minus the quotient of 12 divided by X, the difference is 80, find X

The product of 12.5 and 8 minus the quotient of 12 divided by X, the difference is 80, find X

The equation: 12.5 * 8-12 / x = 80
100-12/x=80
-12/x=-100+80
12/x=100+80
12/x=180
x=12/180
x=1/15

It is known that a minus B = 10.8, a divided by B = 2.6

a--b=10.8 (1)
a/b=2.6 (2)
From (2), it is concluded that:
a=2.6b
By substituting a = 2.6B into (1), we can get:
2.6b--b=10.8
1.6b=10.8
b=6.75
So a = 2.6B = 2.6x6.75 = 17.55

(a of B minus B of a) divided by a of a + B

The original formula = (A & # 178; - B & # 178;) / AB △ (a + b) / A
=(a+b)(a-b)/ab×a/(a+b)
=(a-b)/b