0.8 divided by 0.1 times 0.1 divided by 0.1 times 0.1 divided by "\" \ "[100 0.1] times 0.1

0.8 divided by 0.1 times 0.1 divided by 0.1 times 0.1 divided by "\" \ "[100 0.1] times 0.1

A division by 0.1 and a multiply by 0.1 cancel each other, so the answer is still 0.8

4X of 5 = 2 of 3 + 8
It's 2x out of three. I forgot to add it.

4X of 5 = 2x of 3 + 8 (sixth grade mathematics)
5/4 x=2/3 x+8
4/5 x – 2/3 x = 8
12//15 x – 10/15 x = 8
2/15 x = 8
2X = 8 * 15
X = 60

For a natural number, the sum of the numbers in each digit is 17, and the numbers in each digit are different. What is the minimum number that meets the conditions? What is the maximum number?

17 = 8 + 9, so the minimum is 89; 17 = 0 + 1 + 2 + 3 + 4 + 7, so the maximum is 743210

A number plus 50% of it is one fifth of 7.5. What is the reciprocal of this number?

This number = 7.5 × 1 / 5 △ (1 + 50%) = 1
Reciprocal = 1

What's the reciprocal of a number minus 50% is four-thirds?

This number = 4 / 3 ÷ (1-50%) = 8 / 3
Its reciprocal = 1 △ 8 / 3 = 3 / 8

The sum of an integer and its reciprocal is equal to 20.05, which is______ Its reciprocal is______ ．

This number is an integer, so its reciprocal is less than or equal to 1, because the sum of its reciprocal is 20.05, greater than 1, then its to value is less than 1; so this integer is the integral part of 20.05, that is, 20; its reciprocal is the decimal part of 20.05, that is, 0.05

The sum of an integer and its reciprocal is equal to 20.05?

Let this number be X
x+1/x=20.05
(xsquare + 1) / x = 20.05
x1=20,x2=0.05
The reciprocal of this number is: 1 / 20,20

In the 100 numbers from 1 to 100, find any 10 numbers and make the sum of their reciprocal equal to 1

∵1=1-12+12-13+13-14+… +19-110+110=（1-12）+（12-13）+（13-14）+… +(19-110) + 110 = 12 + 16 + 112 + 120 + 130 + 142 + 156 + 172 + 190 + 110

Can you find 8 numbers from 1 to 100 integers and make their reciprocal sum equal to 1?

∵1=1-12+12-13+13-14+14+… +18=（1-12）+（12-13）+（13-14）+… +(17-18) + 18 = 12 + 16 + 112 + 120 + 130 + 142 + 156 + 18, the 10 numbers can be: 2, 6, 8, 10, 12, 20, 30, 42, 56

Can you find 8 numbers from 1 to 100 integers and make their reciprocal sum equal to 1?

∵1=1-12+12-13+13-14+14+… +18=（1-12）+（12-13）+（13-14）+… +(17-18) + 18 = 12 + 16 + 112 + 120 + 130 + 142 + 156 + 18, the 10 numbers can be: 2, 6, 8, 10, 12, 20, 30, 42, 56