6 yuan for a chicken, 3 yuan for a duck, 2 yuan for a watermelon, 1 yuan for 6 apples. How can I buy 100 things for 100 yuan

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Class 1 of Grade 8 in a middle school plans to use 66 yuan to buy a, B and C water pens with unit prices of 3 yuan, 2 yuan and 1 yuan respectively
Class 1 of Grade 8 in a middle school plans to use 66 yuan to buy a, B and C water pens with the unit price of 3 yuan, 2 yuan and 1 yuan respectively. It is known that B has 2 more pens than a, and a can't buy less than 10 pens, and the cost of buying a can't exceed half of the total cost. If it costs 66 yuan to buy these three pens, how many plans do they have? How many pens did they buy each?
Solving practical problems with the system of linear inequalities of one variable

Let's buy x for a, y for B, and Z for C
There are 3x + 2Y + Z = 66
y+2=x
3x≤33
The solution is x = 10, y = 12, z = 12
Or x = 11, y = 13, z = 7
∵ x = 10, x = 11 all accord with "no less than 10 of a"
There are two schemes, namely

The unit price of a, B and C goods in a store is 2 yuan, 3 yuan and 5 yuan respectively. A person has to buy several of the three goods, and after buying them, he pays 20 yuan in total. Later, the person finds that one of the goods has bought too much and returns two of them, but the salesperson only has 10 yuan for each piece, and there is no change to return. The person has to adjust the quantity of the other two goods to make the total price lower The price remains the same. At this time, the number of items B of the three items purchased by the person is ()
A. 1B. 2C. 3D. 4

∵ return two pieces of this kind of goods, but the salesperson only has 10 yuan for each piece, and there is no change to return. The returned goods are not 5 yuan. ① assuming that the returned goods are 2 pieces of 2 yuan, replace 2 pieces of 3 yuan with 2 pieces of 5 yuan. ② assuming that the returned goods are 2 pieces of 3 yuan, replace 2 pieces of 2 yuan with 2 pieces of 5 yuan. In either case, the total price can remain unchanged. According to ① and ②, at least 2 pieces of 2 yuan can be returned , 3 yuan is only 2 pieces, there are 2 2; 3 3 1 in the combination, and it is found that one of them has bought too much, the original combination of goods is: 3 3 1. Therefore, among the three items purchased by this person, the number of items of type B is three at first, two items are returned, and one item is left. That is, in the end, 1 item of type A, 1 item of type B, and 3 items of type C are bought. At this time, the number of items of type B purchased by this person is 1, so select a

Li Ming's class plans to use 66 yuan of work study income to buy prizes of 3 yuan, 2 yuan and 1 yuan for a, B and C at the same time, It is known that there are two more souvenirs of type B than that of type A, and the cost of type C is not more than half of the total cost. If it costs 66 yuan to buy three kinds of souvenirs of type A, B and C, what are the purchase plans?

Suppose the number of a souvenir is x and that of C souvenir is y,
The quantity of souvenir B is (x + 2),
Then 3x + 2 (x + 2) + y = 66,
That is, y = 62-5x,
And X ≥ 10 and 3x ≤ 662,
The solution is x ≤ 11,
х x = 10 or 11
When x = 10, x + 2 = 12, y = 62-5x = 12;
At this time, the three kinds of souvenirs were 10, 12 and 12
When x = 11, x + 2 = 13, y = 62-5x = 7,
At this time, the three kinds of souvenirs were 11, 13 and 7

From June 1, a supermarket began to provide three kinds of reusable environmental protection shopping bags with a price of 1 yuan, 2 yuan and 3 yuan respectively. Each of these three kinds of environmental protection shopping bags can hold 3 kg, 5 kg and 8 kg of rice respectively. On June 7, Xiaoxing and dad bought three environmental protection shopping bags in the supermarket to hold 20 kg of bulk rice they just bought The bags should at least be paid to the supermarket______ Yuan

According to the meaning of the question, we get: 3x + 5Y + 8 (3-x-y) ≥ 20, the solution is: X ≤ 4 − 3y5, ∵ x ≥ 0, ∵ 4-3y ≥ 0, the solution is: y ≤ 43, ∵ y is a non negative integer, ∵ y can only be equal to 0 or 1. When y = 0, x = 0, z = 3

For binary, ternary, quaternion equations, at least 5 questions

1.2X+5Y=-26
3X-5Y=36
2.2A+6B=-4
2B-6A=-8
3.2X=3Y
4Y=5Z
X+Y+Z=66
4.5X+4Y+Z=0
3X+Y-4Z=11
X+Y+Z=-2
5.X+Y=16
Y+Z=41
Z+A=65
X+Y+Z+A=81

5 yuan 3 fen 1 3 yuan 8 Jiao how should calculate

It's all converted and then calculated
5 yuan 3 fen = 503 Fen, 3 yuan 8 Jiao = 380 Fen
503-380 = 123 points = 1 yuan and 2 jiao and 3 points

Is 135 minutes equal to 2,25 hours

Yes
2.25 hours

How many hours and minutes is 1.2 hours

1 hour 12 minutes

How much is three minus five and five minutes three

-Two and five and three

6 yuan for a chicken, 3 yuan for a duck, 2 yuan for a watermelon, 1 yuan for 6 apples. How can I buy 100 things for 100 yuan