Simple operation of 8.75-3.46-1.8 * 0.3 11 / 39 * 40 6-3 / 2-5 / 4-9 / 8-17 / 16 - 33 / 32

Simple operation of 8.75-3.46-1.8 * 0.3 11 / 39 * 40 6-3 / 2-5 / 4-9 / 8-17 / 16 - 33 / 32

8.75-3.46-1.8 * 0.3 = 8.75-3.46-0.54 = 8.75 - (3.46 + 0.54) = 8.75-4 = 4.7511/39 * 40 = 11 / 39 * (39 + 1) = 11 + 11 / 39 = 11, 116-3 / 2-5 / 4-9 / 8-17 / 16 - 33 / 32 = 6-1-1 / 2-1 / 4-1-1 / 8-1-1 / 16-1-1 / 32 = 1-1 / 2-1 / 2-1 / 4-1 / 8-1 / 16-1 / 32 = 2 / 2-1 / 2

Find 1-3 + 2-6 + 3-9 + +Values of 33-99
Known: 1 + 2 + 3 + 4 + 5 + +31+32+33=17×33

1-3+2-6+3-9+… +33-99
= 1+2+3+...+33 -3-6-9-...-99
= (1+2+3+...+33)- 3(1+2+3+...+33)
= -2(1+2+3+...+33)
= -2*17*33
= -1122

A is a non-zero natural number, 1 / 6 of a is equal to ()
A. A B of B, 6a C, B D of a, 1 of 6A

B.
Because dividing a number is equal to multiplying the reciprocal of the number
A △ 1 / 6 = a × 6 = 6A

Five out of sixteen plus a natural number equals half. What's the natural number?

What do you think

A natural number, use it to remove 266 odd a, 411 odd a + 1, 527 odd a + 2, find out what a is

266 = n × quotient + A,
411 = n × quotient + A + 1,
527 = n × quotient + A + 2
So 266 = n × quotient + a
410 = n × quotient + A
525 = n × quotient + A
If the three equations subtract each other, a will be reduced, and n should be the greatest common divisor 23 of 184, 115 and 299, then a is the remainder 19 of 226 ／ 23

There is a natural number, which can be used to remove 226 odd a, 411 odd a + 1 and 527 odd a + 2, then a=______ ．

410-226 = 184 = 23 × 8525-226 = 299 = 23 × 13525-410 = 115 = 23 × 5 19, that is: a = 19; so the answer is: 19

If a natural number is used to remove 266 odd a, 411 odd a 1 and 527 odd a 2, what is a equal to?

Let X be the natural number
266-a=mx,411-a=nx,527-a=px,(m、n、p∈Z),
——》(n-m)x=145=29*5,(p-n)x=116=29*4,(p-m)x=261=29*9,
——》X is the common divisor 29 of 145, 116 and 261,
——》a=266-29*9=5.

Fill in 1.2.3.4.5.6.7.8.9. In 3 lines and 3 spaces respectively, with 5 in the middle, so that the sum of each horizontal, vertical and oblique line is equal to 15

2.9.4
7.5.3
6.1.8
6 8 is enough
24 for the shoulder
5 in the middle
Nine days and one earth
Just remember the formula

Fill 0-8 in 3 rows and 3 boxes respectively, so that the sum of each horizontal and vertical row is equal to 9
9 numbers are filled in 3 rows and 3 spaces respectively, so that the sum of each horizontal and vertical row is equal to 9

5 6 1
0 4 8
7 2 3
Hope to help you

The data of time and temperature in a test are recorded in the table below
As a result, you will be able to \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\35;160;         20 & #160;                     25
The results show that the temperature of \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\ \35;160;                       85
When is the temperature 34 ℃?

y=3x+10
When y = 34 ℃
34=3x+10
3x=24
x=8