（-60）÷（¾+5/6-11/15-7/12） （3/4+5/6-11/15-7/12）×（-60） （3/4+5/6-11/15-7/12）÷（-60）

（-60）÷（¾+5/6-11/15-7/12） （3/4+5/6-11/15-7/12）×（-60） （3/4+5/6-11/15-7/12）÷（-60）

(3 / 4 + 5 / 6-11 / 15-7 / 12) × (- 60) original formula = 3 / 4 × (- 60) + 5 / 6 × (- 60) - 11 / 15 × (- 60) - 7 / 12 × (- 60) = - 3 × 15-5 × 10 + 11 × 4 + 7 × 5 = - 45-50 + 44 + 35 = - 16 (3 / 4 + 5 / 6-11 / 15-7 / 12) △ (- 60) original formula = (3 / 4 + 5 / 6-11 / 15-7 / 12) × (- 1 / 60)

500X times 4 / 4 divided by 25 = 60
It's the easiest and most urgent

500X * 4 / 4 = 60 * 25, approximately x = 3

60 divided by 1 / 25

60 divided by 1 / 25
=60×25
=1500

5 parts () = () divided by 25 = 0.6 = 18: () = 60%

5 (3) = (15) divided by 25 = 0.6 = 18: (30) = 60%

A number divided by 5 is more than 4 divided by 4 is more than 3 divided by 3 is more than 2, and more than 60?

Your condition "greater than 60" should be wrong, because there will be countless, as long as the number is the common multiple of 5,4,3 minus one, the condition can be satisfied, such as: 119179239, etc.; if it is "less than 60", there will be a unique 59

What is the integral part of 9 / 10 + 99 / 100 + 999 / 1000 +... + 999999 / 10 billion?

Change to (1-1 / 10) + (1-1 / 100) +. + (1-1 / 100000000) = 10 - (1 / 10 + 1 / 100 +. + 1 / 100000000)
Because the sum of the numbers in brackets is less than 1, the integer part is 9

It is known that x = 9 / 10 + 99 / 100 + 999 / 1000 + 999999999 / 100000000, find the integer part of X?

x=（1-1/10）+（1-1/100）+… +（1-1/10000000000）
There are 10 items in total, so the integral part of X is 9

2 divided by 1 in 5, 3 divided by 9 in 10, 6 times 3 in 4

3/108/10

4 out of 5 divided by () 1 out of x2 = 3 out of 10 () divided by 5 out of 8, 5 out of 4 =
4 out of 5 divided by () 1 out of x2 = 3 out of 10 () divided by 5X4 out of 8 = 1

5/8

(x divided by 10 + X divided by 8) times 4 + 5000 = X

(x/10+x/8)×4+5000=x
9x/40×4+5000=x
9x/10+5000=x
x-9x/10=5000
x/10=5000
x=5000÷1/10
x=50000