How many zeros are there at the end of 1 * 2 * 3 * 4 * 5 * 6 *. * 49 * 50 product?

How many zeros are there at the end of 1 * 2 * 3 * 4 * 5 * 6 *. * 49 * 50 product?

The number of factors 5 determines the number of zeros at the end
50 △ 5 = 10
50 △ 25 = 2
10+2=12
1*2*3*4*5*6*…… *There are 12 zeros at the end of 49 * 50

How many zeros are there at the end of the product of 1 × 2 × 3 × 4 × 5 ×. × 50?
I want the formula

The number of factors 5 determines the number of zeros at the end
50÷5=10
50÷25=2
10+2=12
There are 12 zeros at the end of the product of 1 × 2 × 3 × 4 × 5 ×. × 50

If 41 digits 555.55a999.. 99 can be divided by 7, then what is a?

By using the property that 111111 is divisible by 7, the original number is divided from two ends to the middle, every 6 bits: 555555 ,55A99,…… In order to divide the middle 55a99 by 7, according to the "cut three method" divided by 7, there are A99 - 55 = a44 = 100A +

The four digit number 7 ﹣ 4 ﹣ can be divided by 55 to find all such four digit numbers?

According to the meaning of the title: 55 = 5 × 11, 5 and 11 are mutually prime, then the four digit number 7 □ 4 can be divided by 5 and 11 at the same time; if it can be divided by 5, the single digit can only be 0 or 5; if it can be divided by 11, (7 + 4) - (hundred digit + 0) can be divided by 11, that is, 11 - (hundred digit + 0) = 0, the hundred digit can only be 0, and the resulting four digits are: 7040; (7 + 4) - (hundred digit + 5) can be divided by 11, that is, 11- (hundred number + 5) = 0, the hundred number can only be 6, and the four digits obtained are: 7645. There are only two four digits satisfying the conditions: 70407645. A: such four digits are: 70407645

The four digit number 7 ﹣ 4 ﹣ can be divided by 55 to find all such four digit numbers?

According to the meaning of the question: 55 = 5 × 11, 5 and 11 are mutually prime, then the four digit 7 ﹣ 4 ﹣ can be divided by 5 and 11 at the same time; can be divided by 5, the single digit can only be 0 or 5; can be divided by 11, (7 + 4) - (hundred digit + 0) can be divided by 11, that is, 11 - (hundred digit + 0) = 0, the hundred digit can only be 0, the resulting four digits are

The four digit number 7 ﹣ 4 ﹣ can be divided by 55 to find all such four digit numbers?

According to the meaning of the question: 55 = 5 × 11, 5 and 11 are mutually prime, then the four digit 7 ﹣ 4 ﹣ can be divided by 5 and 11 at the same time; can be divided by 5, the single digit can only be 0 or 5; can be divided by 11, (7 + 4) - (hundred digit + 0) can be divided by 11, that is, 11 - (hundred digit + 0) = 0, the hundred digit can only be 0, the resulting four digits are

The four digit number 7 ﹣ 4 ﹣ can be divided by 55 to find all such four digit numbers?

According to the meaning of the question: 55 = 5 × 11, 5 and 11 are mutually prime, then the four digit 7 ﹣ 4 ﹣ can be divided by 5 and 11 at the same time; can be divided by 5, the single digit can only be 0 or 5; can be divided by 11, (7 + 4) - (hundred digit + 0) can be divided by 11, that is, 11 - (hundred digit + 0) = 0, the hundred digit can only be 0, the resulting four digits are

(one and four fifths minus two and five sixths plus three and seven tenths minus four and eight fifths) / (negative 13)
Count degrees, count degrees

28/195

The number a is one fourth, the number B is equal to three fifths of the number a, and the number C is equal to three fifths of the number B. what is the number C?

The number of a is 1 / 4
B is equal to three fifths of A
B is 1 / 4 * 3 / 5 = 3 / 20
C is equal to three fifths of B
Three fifths of B is 3 / 20 * 3 / 5 = 9 / 100
So the C number is
9/100

Three fifths of a is equal to one third of B. then B is () of A

B is 9 / 5 of a