Ask for advice (2 + 1) (22 + 1) (24 + 1) (28 + 1) How much is (264 + 1) + 1?

Ask for advice (2 + 1) (22 + 1) (24 + 1) (28 + 1) How much is (264 + 1) + 1?

(2+1)(2^2+1)(2^4+1)(2^8+1）… (2^64+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1）… (2^64+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1）… (2^64+1)+1
=(2^4-1)(2^4+1)(2^8+1）… (2^64+1)+1
=(2^8-1)(2^8+1）… (2^64+1)+1
=(2^16-1).(2^64+1)+1
.
=(2^64-1)(2^64+1)+1
=2^128-1+1
=2^128
PS: 2 ^ 2 is the second power of 2. 2 ^ 128 is the 128 power of 2

(2+1)(22+1)( 24+1)( 28+1)( 216+1)( 232+1)( 264+1)+1

Original formula = (2-1) (2 + 1) (2 ^ 2 + 1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) (2 ^ 64 + 1) + 1
Continuous use of square difference formula can get = 2 ^ 128-1 + 1 = 2 ^ 128
(2 ^ 2 + 1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) (2 ^ 64 + 1) in the title
(2 + 1) (22 + 1) (24 + 1) (28 + 1) (216 + 1) (232 + 1) (264 + 1), wrong
I have done this problem

Calculation: (1 & sup2; - 2) / (1 + 2) + (2 & sup2; - 3 & sup2;) / (2 + 3) + +（99²—100²）/（99+100）

（1²－2²）/（1+2）+（2²—3²）/（2+3）+…… +（99²—100²）/（99+100）= (1+2)(1-2)/(1+2)+(2+3)(2-3)/(2+3)+...+(99+1000)(99-100)/(99+100)=1-2+2-3+...+99-100=1-100=-99...

Quick calculation 48 + 49 + 50 + 51 + +1478+1479+1480=?

Method 1: (first 48 + last 1480) * number of items / 2
Methods: (48 + 1480) * (1482-47) / 2 = 1 096 340